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    Mad busy here. Everyone confident?

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    (Original post by Krollo)
    Mad busy here. Everyone confident?
    If this exam is not completely standard then I will be mildly annoyed.
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    Good luck guys. May the force exerted on the axis be with you.
    If not take moments all will be good.


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    (Original post by physicsmaths)
    Good luck guys. May the force exerted on the axis be with you.
    If not take moments all will be good.


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    Good luck m8!


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    (Original post by ombtom)
    If this exam is not completely standard then I will be mildly annoyed.
    Only mildly? I'll be dying...

    (Original post by physicsmaths)
    Good luck guys. May the force exerted on the axis be with you.
    If not take moments all will be good.


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    Word.

    Good luck people

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    A cylindrical shell is a hollow cylinder with no caps on right?

    I got 1/3 •M•h^2 but I got so confused

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    It is. I got Mr²/2 + Mh²/3 though.
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    Did people find that easier than last years?
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    (Original post by Bolts)
    Did people find that easier than last years?
    I think the rotational moments questions were easier, but I would think that the other questions were a bit harder than usual, grade boundaries will probably be roughly the same.
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    (Original post by talentedlobster)
    It is. I got Mr²/2 + Mh²/3 though.
    That's the one ¡
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    (Original post by Euclidean)
    A cylindrical shell is a hollow cylinder with no caps on right?

    I got 1/3 •M•h^2 but I got so confused

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    I just did it with ends aswell tbh. **** knows. Did both ways.
    I definately dropped marks tbh. The simple pendulum i am pretty sure i got wrong ,i found stable equilibrium pint so where the COM was then did some next geoemtry moments


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    (Original post by Bolts)
    Did people find that easier than last years?
    Na it was harder i predict 2 marks lower then last yrs boundaries.


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    (Original post by physicsmaths)
    I just did it with ends aswell tbh. **** knows. Did both ways.
    I definately dropped marks tbh. The simple pendulum i am pretty sure i got wrong ,i found stable equilibrium pint so where the COM was then did some next geoemtry moments


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    For the COM did you have it a/2 from the bend to the right and a/2 up?
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    (Original post by Bolts)
    For the COM did you have it a/2 from the bend to the right and a/2 up?
    Yep.
    I made a mistake in MI question did
    MI about diameter of disc is 1/2mr^2 😂.
    Lol cares, got my 85.


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    (Original post by physicsmaths)
    I just did it with ends aswell tbh. **** knows. Did both ways.
    I definately dropped marks tbh. The simple pendulum i am pretty sure i got wrong ,i found stable equilibrium pint so where the COM was then did some next geoemtry moments


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    I think I f****d up. :facepalm:

    Anyone have any numerical answers?

    Q1: -6 i + 25/2 j

    Q2: cos (t) i - 2sin (2t) j

    Q3: (-3, 0, 1) but this was different to the resultant x the vector they give so I probably messed up

    Q4: Really messed up

    Q5: Assuming this is the variable mass

    v = u•ln (5) - 19.6

    Q6: a) omega = 3J/2mga I think
    b) T = 20pi/3 • root {g/5a}

    Q7: b) Y = 7/8 mg
    But I think I was supposed to take 3mg/8 away from mg/2 not add it... FFS

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    (Original post by Mathemagicien)
    I recognise these numbers
    right so I probably got 4/7 right then 😂

    Praying for more method marks than accuracy marks

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    (Original post by Mathemagicien)
    I did, although of course maybe I just made loads of mistakes



    Hmm, I got Mr^2/4 + Mh^2/3

    You did remember that M.I. of circle about its diameter is mr^2/4, not mr^2/2? I remember I initially made that mistake
    It was hollow though so you need the MI of a circular arc about its diameter which is mr^2/2
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    (Original post by Nikulp68)
    It was hollow though so you need the MI of a circular arc about its diameter which is mr^2/2
    It was completely hollow? I don't think it was.
    It was either both ends covered or none since hey said about 1 end implying that it is symmetric.


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    (Original post by physicsmaths)
    It was completely hollow? I don't think it was.
    It was either both ends covered or none since hey said about 1 end implying that it is symmetric.


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    Shoot. My bad. How many marks would that be? Marks lost, that is.
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    (Original post by Mathemagicien)
    Ah

    Oops
    I did it like a rod. :lol: :facepalm:
 
 
 
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