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# Maths year 11 watch

1. (Original post by z_o_e)
Thank you

Also I have quiet a few of these..

Do I measure it in cm and convert it to M?

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I don't know for certain as the context is not shown but go for metres.
2. (Original post by RDKGames)
I don't know for certain as the context is not shown but go for metres.
Yeah I moved on ill ask my teacher.

How's this

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3. (Original post by z_o_e)
Yeah I moved on ill ask my teacher.

How's this

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Correct, though you could just rewrite it as if you can spot what is really happening here.
4. (Original post by RDKGames)
Correct, though you could just rewrite it as if you can spot what is really happening here.
Thank you!

I just did this. Looks incorrect as it says how many years will her cat be worth £6000 and I did not get that.

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5. (Original post by z_o_e)
Thank you!

I just did this. Looks incorrect as it says how many years will her cat be worth £6000 and I did not get that.

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So it would be worth £6000 after 6 full years. You can work out the exact amount of years but I don't think you can do that at GCSE.
6. (Original post by RDKGames)
So it would be worth £6000 after 6 full years. You can work out the exact amount of years but I don't think you can do that at GCSE.
I'm not sure whether it's 6 or 7 years.

6 years is more than £6000

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7. (Original post by z_o_e)
I'm not sure whether it's 6 or 7 years.

6 years is more than £6000

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These questions never make anything clear. Technically speaking, it hits £6000 during it's 7th year so it does NOT fully complete the 7 years which is why I'm saying 6.
8. (Original post by RDKGames)
These questions never make anything clear. Technically speaking, it hits £6000 during it's 7th year so it does NOT fully complete the 7 years which is why I'm saying 6.
How do I work this out

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9. (Original post by RDKGames)
These questions never make anything clear. Technically speaking, it hits £6000 during it's 7th year so it does NOT fully complete the 7 years which is why I'm saying 6.
Heyaa can you help me on the one above please xx

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10. (Original post by z_o_e)
Heyaa can you help me on the one above please xx

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m is the gradient and c is the y-intercept so you can figure this from looking at the graph. For the gradient, just pick 2 different coordinates on the line and find the slope as usual.
11. (Original post by RDKGames)
m is the gradient and c is the y-intercept so you can figure this from looking at the graph. For the gradient, just pick 2 different coordinates on the line and find the slope as usual.
Is this correct

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12. (Original post by z_o_e)
Is this correct

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Looks correct, yes, though it's hard to determine the gradient from a graph like that without any annotation.
13. (Original post by RDKGames)
Looks correct, yes, though it's hard to determine the gradient from a graph like that without any annotation.
Thank you. I find it hard doing it on plain paper lined paper is easier.

This question need explanation please so sorry for being annoying but I need to understand practise papers so I can do them alone.

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14. (Original post by z_o_e)
Is this okay?

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its wrong
power of -4 doesnot mean that you have to multiply it with -4
its mean multiply value by how many times
in this question
2p^-4 = 1/2p^4 =1/2p*2p*2p*2p =1/16p4

hope it make sense
15. (Original post by z_o_e)
Thank you. I find it hard doing it on plain paper lined paper is easier.

This question need explanation please so sorry for being annoying but I need to understand practise papers so I can do them alone.

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Okay so for part A you should consider all the possible combinations from the spinner and the die in order to get a 3. This is a very simple example and I'm sure you can agree that the only way to get a 3 is from getting a 1 and a 2.

So work out the probability that Sally gets a 1 on the spinner, and a 2 on the die, then multiply these probabilities together. You multiply, and NOT add, because this is conditional probability. She will get a 3 on a CONDITION that she get's a 1 followed by a 2 on the respective items.

For part B it's essentially the same thing. List what scores Sally can get that are less than 5 and see how they can be achieved from the two items.
16. (Original post by RDKGames)
Okay so for part A you should consider all the possible combinations from the spinner and the die in order to get a 3. This is a very simple example and I'm sure you can agree that the only way to get a 3 is from getting a 1 and a 2.

So work out the probability that Sally gets a 1 on the spinner, and a 2 on the die, then multiply these probabilities together. You multiply, and NOT add, because this is conditional probability. She will get a 3 on a CONDITION that she get's a 1 followed by a 2 on the respective items.

For part B it's essentially the same thing. List what scores Sally can get that are less than 5 and see how they can be achieved from the two items.

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17. (Original post by RDKGames)
Okay so for part A you should consider all the possible combinations from the spinner and the die in order to get a 3. This is a very simple example and I'm sure you can agree that the only way to get a 3 is from getting a 1 and a 2.

So work out the probability that Sally gets a 1 on the spinner, and a 2 on the die, then multiply these probabilities together. You multiply, and NOT add, because this is conditional probability. She will get a 3 on a CONDITION that she get's a 1 followed by a 2 on the respective items.

For part B it's essentially the same thing. List what scores Sally can get that are less than 5 and see how they can be achieved from the two items.
Is that correct

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18. Not quite for part B. First list all the possible combinations that will give the score of less than 5. There combinations are:

{1,1}
{1,2}
{1,3}

find probabilities for each and add them up
19. (Original post by RDKGames)
Not quite for part B. First list all the possible combinations that will give the score of less than 5. There combinations are:

{1,1}
{1,2}
{1,3}

find probabilities for each and add them up
1/4 + 1/6?

Do I do that 3 times?

Or 1/4 + 3/6

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20. (Original post by z_o_e)
1/4 + 1/6?

Do I do that 3 times?

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yes

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