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Will the real TeeEm please stand up! watch

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    (Original post by TeeEm)
    this question is for clever, determined, motivated people ...
    (I am still waiting for paper A, which clearly got the better of you ...)
    done....


    Spoiler:
    Show
    λ = 0 for the foot of the perpendicular from C to AB

    also on my diagram the quadrilateral was ABQP rather than ABPQ
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    (Original post by TeeEm)
    this tough question is freshly written today during one of my lessons


    Attachment 494751
    I was asked to mention the student, so here it comes
    This vector question was "LIVE AT RAJIV'S
    Too easy my friend.
    Name:  ImageUploadedByStudent Room1452977788.743013.jpg
Views: 84
Size:  135.8 KB
    Name:  ImageUploadedByStudent Room1452977816.773255.jpg
Views: 80
Size:  119.2 KB


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    (Original post by the bear)
    done....


    Spoiler:
    Show
    λ = 0 for the foot of the perpendicular from C to AB

    also on my diagram the quadrilateral was ABQP rather than ABPQ
    Yep same, dropped some perpssss and we are done.


    Posted from TSR Mobile
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    (Original post by the bear)
    done....

    Spoiler:
    Show
    λ = 0 for the foot of the perpendicular from C to AB

    also on my diagram the quadrilateral was ABQP rather than ABPQ
    P and Q are not unique
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    (Original post by physicsmaths)
    Too easy my friend.
    Name:  ImageUploadedByStudent Room1452977788.743013.jpg
Views: 84
Size:  135.8 KB
    Name:  ImageUploadedByStudent Room1452977816.773255.jpg
Views: 80
Size:  119.2 KB


    Posted from TSR Mobile
    Two questions for you
    1. are feeling good about yourself?
    2. would you like me to write a solution?
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    (Original post by TeeEm)
    this tough question is freshly written today during one of my lessons


    Attachment 494751
    I was asked to mention the student, so here it comes
    This vector question was "LIVE AT RAJIV'S
    The pictures get me everytime. :rofl::rofl::rofl:
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    (Original post by TeeEm)
    Two questions for you
    1. are feeling good about yourself?
    2. would you like me to write a solution?
    Chillll, I was joking it is a nice question. Tbh It reminds me of an edexcel question but i just can't remember what year it was.
    Is it right though yh?


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    (Original post by physicsmaths)
    Chillll, I was joking it is a nice question. Tbh It reminds me of an edexcel question but i just can't remember what year it was.
    Is it right though yh?


    Posted from TSR Mobile
    I am chilled ...


    (you did not answer neither question)
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    (Original post by Star-girl)
    The pictures get me everytime. :rofl::rofl::rofl:
    one of my trademarks
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    (Original post by TeeEm)
    one of my trademarks
    You do it well. :hat2:
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    (Original post by TeeEm)
    I am chilled ...


    (you did not answer neither question)
    Oh kl,
    q2. if I did it wrong, yes write a solution.
    q1,I always feel good


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    (Original post by physicsmaths)
    Oh kl,
    q2. if I did it wrong, yes write a solution.
    q1,I always feel good


    Posted from TSR Mobile
    I have no idea if you did it right as I have difficulty reading your scripts... the answer is there so if you got it you must got it right.

    the solution I will write anyhow as this goes into one of my papers
    whole question is either 5 or 6 marks.
    it looks that you went to a lot of bother there
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    (Original post by TeeEm)
    this tough question is freshly written today during one of my lessons


    Attachment 494751
    I was asked to mention the student, so here it comes
    This vector question was "LIVE AT RAJIV'S
    I got it
    But you definitely don't want to see the state of my workings
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    (Original post by 13 1 20 8 42)
    I got it
    But you definitely don't want to see the state of my workings
    I hope you did it the clever way
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    (Original post by 13 1 20 8 42)
    I got it
    But you definitely don't want to see the state of my workings
    Can you read/understand my working?
    I thought it was nice n neat.


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    (Original post by physicsmaths)
    Can you read/understand my working?
    I thought it was nice n neat.


    Posted from TSR Mobile
    Can read it fine, pretty sure I get what you've done. My route was a bit odd; I let (a, b, c) be a direction vector of the perpendicular between the lines and then used the dot product and the fact that they had to intersect to find relationships between (a, b, c) and then just let a = 1. Then solved for the necessary parameter needed in getting from one line to the other and used the resulting distance in the trapezium formula along with 4|AB| + |AB| getting 5root(3)/2 * (2root(6)) like you did. Sounds more long-winded than it is probably
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    (Original post by TeeEm)
    I hope you did it the clever way
    It would be a momentous occasion if I ever did a problem the clever way
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    (Original post by physicsmaths)
    Can you read/understand my working?
    I thought it was nice n neat.


    Posted from TSR Mobile
    (Original post by 13 1 20 8 42)
    It would be a momentous occasion if I ever did a problem the clever way
    ...
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    (Original post by TeeEm)
    ...
    I basically found d, then did area of a trapezium. This way is nice aswell.



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    (Original post by physicsmaths)
    I basically found d, then did area of a trapezium. This way is nice aswell.



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    thank you that you approve!
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