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6th Years and Leavers :: Chat Thread #2 :: Revenge of the Ape watch

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    (Original post by ukdragon37)
    Except me and my partner was the only pair who didn't get the "star" at our hardware practical because of some undiagnosed fault in the circuit :mob:
    Ah, unlucky. It doesn't really matter in the end, though, does it? I assume that the hardware pracs are just 'ticks' like ML and Java?

    And Physics sucks.
    QFT. I ignored our subject contacts who all said 'don't take physics' and, in one case, 'I ignored our second years who all said "don't take physics" - I was wrong: don't take physics'. I think I shall be incrementing this recursion depth once more next year.
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    (Original post by TheUnbeliever)
    Ah, unlucky. It doesn't really matter in the end, though, does it? I assume that the hardware pracs are just 'ticks' like ML and Java?
    They are, but when people see the tick list they are going to :hahaha: at you
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    You! Yes....you. Entertain me.
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    (Original post by Madjackismad)
    You! Yes....you. Entertain me.
    :juggle:

    Ta da.
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    (Original post by Madjackismad)
    You! Yes....you. Entertain me.


    Or, if you're willing to wait...
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    (Original post by xo-Heva)
    :juggle:

    Ta da.
    :rofl: This has given me a fit of the giggles.
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    (Original post by TheUnbeliever)
    :rofl: This has given me a fit of the giggles.
    :awesome:
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    (Original post by TheUnbeliever)
    QFT. I ignored our subject contacts who all said 'don't take physics' and, in one case, 'I ignored our second years who all said "don't take physics" - I was wrong: don't take physics'. I think I shall be incrementing this recursion depth once more next year.
    Aww guys... :p:
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    (Original post by Meteorshower)
    Aww guys... :p:
    :rofl: I'm sorry, but the truth hurts! Incidentally, I believe I still owe you a non-alcoholic drink. I'm visiting friends at St As in December (because we finish about two weeks earlier than you ), if you're interested. :p:
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    Wondering if someone can help me. I have the question:

    Solve for n \in\mathbb{N}, \displaystyle \binom{2n}{2} = 66

    It's fairly simple to get ut to \frac{(2n)!}{(2n-2)!}=128 but can I just use an iterative method from here, or is there a way to solve it algebraically. It's just that we didn't really go into much detail about the ^n\mathrm{C}_r thing. :p:

    I acually have an answer, but I had to use an iterative method. It's worth 6 marks as well, which suggests I need to be doing more work than I am doing.
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    (Original post by namedeprived)
    Wondering if someone can help me. I have the question:

    Solve for n \in\mathbb{N}, \displaystyle \binom{2n}{2} = 66

    It's fairly simple to get ut to \frac{(2n)!}{(2n-2)!}=128 but can I just use an iterative method from here, or is there a way to solve it algebraically. It's just that we didn't really go into much detail about the ^n\mathrm{C}_r thing. :p:

    I acually have an answer, but I had to use an iterative method. It's worth 6 marks as well, which suggests I need to be doing more work than I am doing.
    You might like to know that:
    \displaystyle \binom{2n}{2} = 66 = \binom{2n+1}{2} - \binom{2n}{1} = \binom{2n+1}{2} - 2n

    That should save you mucho working

    Also think about why that statement is true.
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    Good night peoples xxx
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    (Original post by xo-Heva)
    Good night peoples xxx
    Night

    (Goddamn this maths example sheet! :mob: Complex numbers in a geometric series is an abomination against mankind)
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    Hey guys

    How is everyone tonight?
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    (Original post by ukdragon37)
    You might like to know that:
    \displaystyle \binom{2n}{2} = 66 = \binom{2n+1}{2} - \binom{2n}{1} = \binom{2n+1}{2} - 2n

    That should save you mucho working

    Also think about why that statement is true.
    Thanks. To be honest, the only thing I actually know about ^n\mathrm {C}_r is that it equals \frac{n!}{(n-r!)(r!)} so I'll need to look up more on it. Although I sort of understand what you say.

    I'm off to bed now as well. Night!
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    (Original post by namedeprived)
    Thanks. To be honest, the only thing I actually know about ^n\mathrm {C}_r is that it equals \frac{n!}{(n-r!)(r!)} so I'll need to look up more on it. Although I sort of understand what you say.

    I'm off to bed now as well. Night!
    Did you get the answer though using that method? A thing that might rattle your brain more is that there is a -ve solution for n

    Night.
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    (Original post by ukdragon37)
    Complex numbers in a geometric series is an abomination against mankind
    :hahaha:
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    (Original post by TheUnbeliever)
    :hahaha:
    You try doing F13a and b then :mad: (Without using multiple angle formulae or expanding out brackets, ha! :p: )
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    (Original post by ukdragon37)
    You try doing F13a and b then :mad:
    No, you see, the difference between you and I is that I can blissfully put off doing them for about a week, whilst you have little option but to do them now or incur the wrath (or lack thereof) of your supervisor. Consequently, I think I'll just, er, not.
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    (Original post by TheUnbeliever)
    No, you see, the difference between you and I is that I can blissfully put off doing them for about a week, whilst you have little option but to do them now or incur the wrath (or lack thereof) of your supervisor. Consequently, I think I'll just, er, not.
    :mad2:

    :p: I've already been told by my subject parents I try far too hard. "Just pretend you never understood the question," they say "the extra hours working on a question is not worth the supervisor just showing you the answer anyway in the end."
 
 
 
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