EL77
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#161
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#161
(Original post by Arsey)
Well you should get 2 marks for e).

as for f) if you said 0.4038 is close to 0.4 so suitable that should get you a mark.


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oh okay i see, thank you, at least thats only one mark lost in that question. also in 4c do you think i would have got any marks for doing P(127<L<133), and when evaluating the skewness i wrote weak positive correlation not just positive correlation? is that correct?
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akrubas
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#162
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#162
Thanks for the mark scheme I predict roughly 66-70 depending on how method marks are structured, as I fudged up a part B of a question and then that lead me to make mistakes on every part except part C, but still thank you
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EL77
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#163
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#163
(Original post by Arsey)
Well you should get 2 marks for e).

as for f) if you said 0.4038 is close to 0.4 so suitable that should get you a mark.


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btw for f i think i wrote 100 x 0.4038 which gives you 40 people which is what is predicted in the table, rather then just writing 40/100 = 0.4038. thats technically saying the same thing right?
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TanishaBellum
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#164
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#164
(Original post by Humzah96)
Sorry having trouble with the app


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I also worked it out for B or Not C! I got 0.89...

I then worked it out correctly at home and got 0.44. Stupid mistake really!

Would I get 1 mark for working or something?
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GodiffL
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#165
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#165
For part 6A, i wrote that the probability for x was 2/6 instead of 1/3.. Will i loose any marks for not putting it in its simplest form??
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Arsey
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#166
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#166
(Original post by mrcool1995)
normal distribution last part...i worked out greater than 133 probability.....how many marks out of 4 will i get. 2?
already answered that one
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Arsey
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#167
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#167
To everyone asking about P(L>133)

if you worked this out correctly you will get 2/4
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Arsey
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#168
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#168
(Original post by Humzah96)
Also arsey i didnt draw a tree diagram i drew a sample space, clearly circled relevnt outcomes and wrote my answer as 5/12 then i said which die is correct in each case is that four marks?


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sounds fine for 4 marks
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Arsey
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#169
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#169
(Original post by GodiffL)
For part 6A, i wrote that the probability for x was 2/6 instead of 1/3.. Will i loose any marks for not putting it in its simplest form??
no
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ljh950912
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#170
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Looking at the wording of 4c,
I think the answer 0.0139. This is because the question doesn't clarify that the phone was turned on at the beginning of the journey, at 127 hours. Therefore we cannot use the 'given that' equation for this. Well, this is what I think.


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Arsey
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#171
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#171
(Original post by TanishaBellum)
I also worked it out for B or Not C! I got 0.89...

I then worked it out correctly at home and got 0.44. Stupid mistake really!

Would I get 1 mark for working or something?
no
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GodiffL
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#172
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#172
(Original post by Arsey)
no
Thanks!
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cera ess six
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#173
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#173
(Original post by Arsey)
X
irrelevant to S1 but you have any predictions for C3 this Jan? you predicted the 'Sum of' formula for C2 in may!
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Arsey
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#174
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#174
(Original post by EL77)
btw for f i think i wrote 100 x 0.4038 which gives you 40 people which is what is predicted in the table, rather then just writing 40/100 = 0.4038. thats technically saying the same thing right?
you will get the 2 marks for e) if what you wrote above was your answer for f) you will probably get 1 mark.
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EL77
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#175
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#175
(Original post by Arsey)
you will get the 2 marks for e) if what you wrote above was your answer for f) you will probably get 1 mark.
oh okay thank you
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otrivine
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#176
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#176
(Original post by Arsey)
you will get the 2 marks for e) if what you wrote above was your answer for f) you will probably get 1 mark.
Hi arsey how are you

quick question for D1 do you think scheduling could come up and what do u predict will be the D1 harder than june 2012
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Arsey
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#177
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#177
(Original post by ljh950912)
Looking at the wording of 4c,
I think the answer 0.0139. This is because the question doesn't clarify that the phone was turned on at the beginning of the journey, at 127 hours. Therefore we cannot use the 'given that' equation for this. Well, this is what I think.


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I made the same point, very poorly worded, but having seen the actual mark scheme I know you are wrong.
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dank-knight
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#178
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#178
Hey just wamted to point out your last question is wrong
your b join c should be be 0.09 check it with a join b 0,35 x 0.45 does not equal to 0.13

Instand, you should use the fact that it is mutual exclusive to find auc=0.65 and then you find the answer.

I used your method too, so i know its wrong. My friend told me the right method afterwards but i forgot it
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chignesh10
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#179
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#179
(Original post by Arsey)
I made the same point, very poorly worded, but having seen the actual mark scheme I know you are wrong.
You already have the actual mark scheme!?!

What does it say for the wordy question in number 1 and the wordy question in the normal distribution>?
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ljh950912
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#180
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#180
(Original post by Arsey)
I made the same point, very poorly worded, but having seen the actual mark scheme I know you are wrong.
Is there any possibility that the exam board will accept both answers or something? Having seen what people have said, almost half of the people got 0.0139. In addition, bad wording is kinda their fault, isn't it?


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