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    (Original post by PreppyNinja)
    You know the intersection question in question 10? (The first section B question ) Will you get away by writing that x=3root16 rather than 12? I wrote it last minute and my friend told me it simplified to 12? :/

    I don't wanna lose that mark
    May depend if they wanted it in it's simplest form, but technically it's the same value so you could have put anything equivalent to 12!
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    absolute trick of a question when you think you need to state the full coordinates - OCR will penalise that error but I got it right too - so glad I did a similar q in a past paper


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    what did you guys get for the rearanging question?

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    (Original post by jojo19apr)
    May depend if they wanted it in it's simplest form, but technically it's the same value so you could have put anything equivalent to 12!
    Hope so. Was the Y-value 2root11?
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    (Original post by Dan_JR_12)
    Yeah I got 3n^2 + 2 and divided it by three to show that would not give you an integer. To be on the safe side, I also used 5 in the equation so show it did not work using actual numbers rather than just equations
    3n^2 is clearly divisible by 3, so when you add 2 it never will be That's the simplest way I could look at it
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    (Original post by Rubyturner94)
    what did you guys get for the rearanging question?

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    Positive square root something ...


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    For the last question I got k=0 and k=4. I got that because y= - x + k, it had a gradient of -1 so the points on the curve must have done too. Then all I could think to do was differentiate (which as a retaker I can do but I know most of you may not have seen that yet), to find the x coordinates of where the gradient was -1 on the graph. Both seemed to match up graphically, so I hoped it worked ok!
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    (Original post by Rubyturner94)
    what did you guys get for the rearanging question?

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    I think the equation went:

    V=1/3*pi*r2*(a+b)
    3V=pi*r2*(a+b)
    3V/pi=r2*(a+b)
    3V/(pi*(a+b))=r2
    r=(3V/(pi*(a+b))1/2


    Hope that helps.
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    (Original post by Rubyturner94)
    what did you guys get for the rearanging question?

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    I don't remember it fully. But it was r= square root 3v over pie minus (a+b) Or something along those lines.
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    (Original post by Deceived)
    I think the equation went:

    V=1/3*pi*r2*(a+b)
    3V=pi*r2*(a+b)
    3V/pi=r2*(a+b)
    3V/(pi*(a+b))=r2
    r=Pos/Neg (3V/(pi*(a+b))1/2


    Hope that helps.
    Positive square root - r>0!!!


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    (Original post by krishkmistry)
    I think I've lost at max 20 marks on this paper - I need ideas of grade boundaries - especially for an A ? Anyone predict - btw though 20 marks is a lot of leeway I think for how many marks I lost


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    They won't know grade boundaries until they have all of the final results, then they adjust the boundaries to have a certain number of candidates walking away each grade. Hence for a hard paper they are lowered and vice versa, this seemed a reasonably fair paper so the boundaries may be slightly higher. But the general guide is 80% = A, 70% = B, 60% = C, 50% = D, 40% = E and 40% > U ........ Hope that gave you a vague idea!
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    (Original post by Deceived)
    I think the equation went:

    V=1/3*pi*r2*(a+b)
    3V=pi*r2*(a+b)
    3V/pi=r2*(a+b)
    3V/(pi*(a+b))=r2
    r=Pos/Neg (3V/(pi*(a+b))1/2


    Hope that helps.
    It cant be postive and negative square root because it said r>0
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    You know the g(x)=+15 or something? How did you do that? It's the only question I left
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    (Original post by PreppyNinja)
    You know the g(x)=+15 or something? How did you do that? It's the only question I left
    -24+15


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    (Original post by krishkmistry)
    -24+15


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    ****. I coulda done that! :/
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    (Original post by Soho32)
    It cant be postive and negative square root because it said r>0
    Easy trick - thank god I noticed that


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    (Original post by Rubyturner94)
    which y intercept?

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    Where the circle crossed, well that's what I got for that question too!!!
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    (Original post by krishkmistry)
    Positive square root - r>0!!!


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    oh wow I think I've slipped up on that too, can't believe I didn't realise the significance of r > 0 in the question!
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    Anyone remember the equations of the two lines in question 2, section A? (intersection question).
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    (Original post by PreppyNinja)
    ****. I coulda done that! :/
    I'm sure it was that because y moves up by 15 so -24 +15 =-9 - anyone confirm this ?


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