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    (Original post by mohammedhz)
    That exam was a flipping screwjob 😅😅😅 ive dropped at least 10 marks
    10 marks isn't too bad at all. I'd say it was harder than last year and 65 marks would have got you 94UMS
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    I think the paper was ok, not too difficult. From what i read here i got it all right apart from last part of Q1 andthe value of k. I got the correct inequality but in a rush i said k = 40 not 39. I hoping for 72/75
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    (Original post by Programming_Nerd)
    This is what I got too. The root of X is -a and -b so x^2 = a^2 and b^2, and they're looking for a^2 and b^2.

    So you should've got something like a^2 = -45/4 = b^2

    You didn't actually have to involve imaginary numbers
    Thought the roots of the quadratic a^2 -1 and b^2 -1? I used the quadratic formula to solve and then just added 1 to get a^2 and b^2 on its own.
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    What a horrible paper!
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    (Original post by Programming_Nerd)
    This is what I got too. The root of X is -a and -b so x^2 = a^2 and b^2, and they're looking for a^2 and b^2.

    So you should've got something like a^2 = -45/4 = b^2

    You didn't actually have to involve imaginary numbers
    No the root of x was a^2 - 1 and b^2 - 1
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    https://www.youtube.com/watch?v=YjnkV_tsjn0
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    I got 4x^2 +53=0 ?
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    (Original post by a123a)
    I got 4x^2 +53=0 ?
    Don't think that's right. A few people got 4x^2 + 45 on here and others in my exam.
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    Think I messed up the one on the transformation being a combination of two things by using A^4 and not A. Can anyone confirm the question? Will that be no marks?
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    (Original post by -jordan-)
    Don't think that's right. A few people got 4x^2 + 45 on here and others in my exam.

    I don't understand how? The product of the new roots were, 53/4?

    Could someone show me?
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    Do you think anyone will be able to do an unofficial mark scheme for this exam? 😂😂
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    (Original post by a123a)
    I don't understand how? The product of the new roots were, 53/4?

    Could someone show me?
    Got the product of the new roots to be 45/4. a+b was -3, ab was 7/2

    (a^2 -1)(b^2 - 1) = a^2b^2 -b^2 - a^2 +1 which is (ab)^2 - (a^2 + b^2) + 1
    a^2 + b^2 = (a+b)^2 - 2(ab) = (-3)^3 - 2(7/2) = 2

    so the product is (7/2)^2 - 2 + 1 which is 45/4
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    (Original post by -jordan-)
    10 marks isn't too bad at all. I'd say it was harder than last year and 65 marks would have got you 94UMS
    Yh i hope the grade boudaries will be lower than last years paper i found this harder thab last years exam and i got 72/75 in that for it in my mock
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    (Original post by a123a)
    I don't understand how? The product of the new roots were, 53/4?

    Could someone show me?
    It wasnt.it was (ab)^2 -a^2-b^2+1. So youd get 49/4 -2 +1 which is 45/4
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    what did people get for the integration question?
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    (Original post by -jordan-)
    Got the product of the new roots to be 45/4. a+b was -3, ab was 7/2

    (a^2 -1)(b^2 - 1) = a^2b^2 -b^2 - a^2 +1 which is (ab)^2 - (a^2 + b^2) + 1
    a^2 + b^2 = (a+b)^2 - 2(ab) = (-3)^3 - 2(7/2) = 2

    so the product is (7/2)^2 - 2 + 1 which is 45/4
    Oh of course! I've dropped more marks then.
    How would you do the next part then?
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    (Original post by tanyapotter)
    what did people get for the integration question?
    No finite limit as it tends to infinity
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    (Original post by Programming_Nerd)
    This is what I got too. The root of X is -a and -b so x^2 = a^2 and b^2, and they're looking for a^2 and b^2.

    So you should've got something like a^2 = -45/4 = b^2

    You didn't actually have to involve imaginary numbers
    OMG i thought it was +/-3root2i but i hought that!! also what about the integration one about the limits?
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    (Original post by a123a)
    Oh of course! I've dropped more marks then.
    How would you do the next part then?
    Used the quadratic formula to find the imaginary roots, then one is equal to a^2 -1 and one is equal to b^2 - 1
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    What so you think an A will be in this paper?
 
 
 
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