You are Here: Home >< Maths

# OCR MEI C3 Mathematics June 2016 - Official Thread Watch

Yeah, I was a bit rushed... Will I get full marks on that part for correct coordinates and writing down y=0.5x without actually showing how I got it, as I didn't have time?
You might lose a method mark but you shouldn't lose any more than 1 I think
2. (Original post by SuruthiG)
very last q, about geometrical properties of f(x), what did you guys put
3. (Original post by jirapat121)
yeah very sure because I did a paper yesterday and they asked the same question "prove that it was divisible by 3" and the mark scheme said to put odd x odd is divisible by 3
11*13=143

143 is not divisible by 3

so odd*odd=odd but isnt necessarily divisible by 3
4. (Original post by Maligaha)
Im pretty sure you have substituted 0 twice....Attachment 554067

This is what I got
5. (Original post by sonron202)
This is what I got
Yessss... That's what I got too
6. [QUOTE=sonron202;65975579]This is what I got[/QUOTE
Thank god people were making me nervous....
7. for geometrical properties it was symmetrical about the line 1/4lnk
8. (Original post by Danny_L)
I got k-1
yes same
9. (Original post by mrk1357)
11*13=143

143 is not divisible by 3

so odd*odd=odd but isnt necessarily divisible by 3
but I thought the equation was (2^n+1)(2^n-1) ?
10. (Original post by Maligaha)
Im pretty sure you have substituted 0 twice....Attachment 554067
No just once that would be a crazy thing to do
11. Cocked up the proof (although I probably got a decent amount of method marks) and the area question at the end but other than that it was a nice exam imo! Hopefully I didn't make too many stupid mistakes throughout the paper but I'm hoping for an A
12. (Original post by Alexw1812)
No just once that would be a crazy thing to do
It looks like you have....
13. (Original post by jirapat121)
but I thought the equation was (2^n+1)(2^n-1) ?
Yes, so 11 and 13 can't be produced by the equation. I am just saying that you can't prove it generally by saying odd*odd is always divisible by 3, because it is not. Here's what I did:

You had to factorise it to (2^n -1)(2^n +1).

If the remainder of (2^n -1) after dividing by 3 is zero, the whole thing clearly must be divisible.

If the remainder of (2^n -1) after dividing by 3 is 1, (2^n +1) must be divisible, so the whole thing must be divisible.

The remainder of (2^n -1) after dividing by 3 is never 2, because then 2^n would be divisible by 3, but it can't as it is a power of 2, so it can only be 1 or 0.
14. Beautiful paper, 71/72 for me, lowest 68/72
This is what I remember:

Odd * odd = odd so divisible by 3

Area = 19/12
ak+b = k-1
4ln(4)-4
Y=(1/2)x
dr/dt = 0.05 m per minute question 3ii
P=(-4, -2)
x = ln2 question 2
x=-1 and x=-1/3
dy/dx=1/(2cos2y)
15. (Original post by Alexw1812)
No just once that would be a crazy thing to do
It was k-1 because it was between 1/2lnk not 1/4lnk

16. I got 55/12 for the area in q8, can someone tell me where I went wrong please? (sorry it's sideways)
17. (Original post by Crozzer24)
Yeah I got something ln in it to, it was by parts and u was lnx so there must have been a ln in the answer.
No it was just 8 i got that
18. If anyone has any questions about the paper I'll answer them, fairly certain I got full marks so I'm happy to help out
19. (Original post by daisyn97)
consecutive odd numbers - one is a factor of 3, so product will be divisible by 3?
If you have 2 consecutive odd numbers, it is still possible that none of them is divisible by 3, like in the case of 11 and 13.

See my previous post for how you can prove it.
20. (Original post by gemdarkstone)
hmmm, i got -4ln4-4 (which i know realise should be 4ln+4...)
not sure who's right tho
No it should be 4ln4-4

TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Updated: May 9, 2017
Today on TSR

Can you relate?

### My alarm went off in an exam!

Discussions on TSR

• Latest
• ## See more of what you like on The Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

• Poll
Useful resources

Can you help? Study help unanswered threadsStudy Help rules and posting guidelinesLaTex guide for writing equations on TSR

## Groups associated with this forum:

View associated groups
Discussions on TSR

• Latest
• ## See more of what you like on The Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

• The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE