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    (Original post by babyetu)
    It said considering the laws of motion, which would be Newton's 3rd law. This is because the jet exerts a force on the air and the air exerts an equal and opposite force on the jet, basically.
    Yeah, that's what I thought; was wondering why people also used second law - doesn't hurt I guess.
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    1700m (2.s.f) distance travelled by plane, anyone ?
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    (Original post by money-for-all)
    1700m (2.s.f) distance travelled by plane, anyone ?
    I got around 850 I think since using the SUVAT with + 2as you had to divide by 2.
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    (Original post by money-for-all)
    1700m (2.s.f) distance travelled by plane, anyone ?
    How did you get that answer? What did you get for deceleration on the question before that?
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    (Original post by money-for-all)
    1700m (2.s.f) distance travelled by plane, anyone ?
    No I got like 800 and something. Deceleration was like 2.7, v=0 and u=68

    (0-68^2)/(2x-2.7) rearranging v^2 = u^2 + 2as to (v^2 - u^2)/2a
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    (Original post by anishnaik)
    How did you get that answer? What did you get for deceleration on the question before that?
    i got 2.7
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    What did everyone get for the last 4 marker (the energy of the photons emitted as a result of annihilation)?
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    Someone make an unofficial markscheme please
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    someone send markscheme
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    (Original post by Akashi)
    What did everyone get for the last 4 marker (the energy of the photons emitted as a result of annihilation)?
    Converted MeV to eV (which is MeVx10^6) then converted that to Joules. Then I just rearranged E=hf and got the frequency.
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    (Original post by babyetu)
    Converted MeV to eV (which is MeVx10^6) then converted that to Joules. Then I just rearranged E=hf and got the frequency.
    Yup, I got something to the x10^23 I think. Felt a bit big so was unsure.
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    Yeah pretty sure mine was to the same power.
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    Why do 2 photons have to be created instead of just 1 during annihilation? I talked about conservation of energy and momentum, but not sure if it's right.
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    (Original post by money-for-all)
    1700m (2.s.f) distance travelled by plane, anyone ?
    I got 1700 something yea
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    (Original post by Akashi)
    Yup, I got something to the x10^23 I think. Felt a bit big so was unsure.
    think u also have to convert MeV to Joules
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    (Original post by tsr1998)
    Why do 2 photons have to be created instead of just 1 during annihilation? I talked about conservation of energy and momentum, but not sure if it's right.
    Don't think energy has any relevance since it's conserved in a single or dual photon.
    I talked about momentum is conserved and about that they have to go in the opposite direction at the same speeds as the colliding particles did or something along the lines of that.
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    (Original post by kylepinto123456)
    I got 1700 something yea
    are you being honest , if so , then high five bruh !!!

    everyone else getting 800 pfft....
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    (Original post by tsr1998)
    Why do 2 photons have to be created instead of just 1 during annihilation? I talked about conservation of energy and momentum, but not sure if it's right.
    I said because certain factors such as baryon number and charge have to be conserved so an antiparticle is created etc. etc.
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    (Original post by kylepinto123456)
    think u also have to convert MeV to Joules
    That is after conversion...
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    (Original post by money-for-all)
    are you being honest , if so , then high five bruh !!!

    everyone else getting 800 pfft....
    v^2 = u^2 + 2as

    v = 0
    u = 68
    a = -2.7

    -(68^2)/2x-2.7 = s

    s = 856.296
    = 8.6 x10^2 (2 s.f.)
 
 
 
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