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    (Original post by Ethan100)
    Meet you in princes street tomorrow, I'll meet jeff at Union Square and we will get a train to Edinburgh
    Meanwhile I'm alone in Ayrshire :/
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    (Original post by sameehaiqbal)
    Nah Yusuf's gonna pussy out. Just bring yourself
    Who the f is Yusuf?

    Of course he's going to bring himself. He's not bringing a random "Yusuf" too!!
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    When Aberdeen folk call Princes St "Princess" St :facepalm:
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    (Original post by .Jeff458)
    Who the f is Yusuf?

    Of course he's going to bring himself. He's not bringing a random "Yusuf" too!!
    bruv
    you are soooooooo good at lying
    mmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm mm oh my gawd stop ****in lying
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    (Original post by sameehaiqbal)
    Nah Yusuf's gonna pussy out. Just bring yourself
    YAS, His name is Yusuf
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    (Original post by Ethan100)
    Don't even ask. I don't even know.
    I blame the so called Jeff.
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    (Original post by Ethan100)
    YAS, His name is Yusuf
    Whose? You're confusing me now :/ The pair of you!
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    We should talk about Physics cos the exam is in like 75 hours :/
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    (Original post by .Jeff458)
    Whose? You're confusing me now :/ The pair of you!
    Didn't you get banned before?
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    (Original post by sameehaiqbal)
    We should talk about Physics cos the exam is in like 75 hours :/
    Plenty of time, just remember your circuits and formulas

    Its Higher Physics that you should be worried about, its a beast.
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    (Original post by Yammy)
    Didn't you get banned before?
    5 times, yeah :/

    (Original post by Yammy)
    Plenty of time, just remember your circuits and formulas

    Its Higher Physics that you should be worried about, its a beast.
    Yeah. Higher is a bugger to revise for
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    (Original post by Yammy)
    Plenty of time, just remember your circuits and formulas

    Its Higher Physics that you should be worried about, its a beast.
    Yeah I glanced over the course content, looks pretty solid
    I struggle the most with circuits and just electricity in general apart from the Gas Law's and the Conservation of Energy which I find easy to understand. Really scared for the electricity questions
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    Are semiconductor diodes in the course ?
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    (Original post by Ethan100)
    Are semiconductor diodes in the course ?
    No. I asked that already before and apparantly its a part of higher not Nat 5. Its in my how to pass book which is why i asked. publishers should be more careful when producing these books
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    (Original post by sameehaiqbal)
    No. I asked that already before and apparantly its a part of higher not Nat 5. Its in my how to pass book which is why i asked. publishers should be more careful when producing these books
    Thanks

    Do you know when you are supposed to use

    Ek= Ep ?
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    (Original post by Ethan100)
    Thanks

    Do you know when you are supposed to use

    Ek= Ep ?
    Yes so you would use that in the "Conservation of Energy". Let me give you an example so you can understand it because it is quite tricky.

    Example:

    A 3.0kg ball is dropped from a height of 2.0m
    a) Calculate its potential energy
    b) Calculate its speed just as it hits the ground.

    a) You would simply do Ep=mgh i.e 3.0 x 9.8 x 2.0
    = 58.8j
    = 59j
    b) Well to calculate the speed you would need the kinetic energy right? But you aren't given it so you are to assume the potential energy has been converted to kinetic energy. Also you can use your common sense because when a ball is dropped it's moving and kinetic energy is the energy in a moving object.

    So: Ek = 0.5mv^2
    v^2 = 59/(0.5 x 3.0)
    v^2 = 39.3
    v = 6.3ms-1

    However you can also do this question algebraically. This is where Ep=Ek comes in.

    Ep=Ek (because potential energy is converted to kinetic energy)
    mgh=0.5mv^2
    gh=0.5v^2
    2gh=v^2
    v = squareroot of 2 x 9.8 x 2.0
    = squareroot of 39
    = 6.3ms-1

    I remember when you were trying to help me with that Gravitational Potential Energy Question from a pastpaper relating to the ball dropping etc...
    You used the algebraic method to find the answer and it was right but you deleted it

    So I think you know what you're doing
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    (Original post by sameehaiqbal)
    Yes so you would use that in the "Conservation of Energy". Let me give you an example so you can understand it because it is quite tricky.

    Example:

    A 3.0kg ball is dropped from a height of 2.0m
    a) Calculate its potential energy
    b) Calculate its speed just as it hits the ground.

    a) You would simply do Ep=mgh i.e 3.0 x 9.8 x 2.0
    = 58.8j
    = 59j
    b) Well to calculate the speed you would need the kinetic energy right? But you aren't given it so you are to assume the potential energy has been converted to kinetic energy. Also you can use your common sense because when a ball is dropped it's moving and kinetic energy is the energy in a moving object.

    So: Ek = 0.5mv^2
    v^2 = 59/(0.5 x 3.0)
    v^2 = 39.3
    v = 6.3ms-1

    However you can also do this question algebraically. This is where Ep=Ek comes in.

    Ep=Ek (because potential energy is converted to kinetic energy)
    mgh=0.5mv^2
    gh=0.5v^2
    2gh=v^2
    v = squareroot of 2 x 9.8 x 2.0
    = squareroot of 39
    = 6.3ms-1

    I remember when you were trying to help me with that Gravitational Potential Energy Question from a pastpaper relating to the ball dropping etc...
    You used the algebraic method to find the answer and it was right but you deleted it

    So I think you know what you're doing
    Wowww thankss Yeah Method 2 is the way I got taught, just forgot how to do it really. I see that you took away the m from both sides, what if it gives you the mass would you substitute the number ?

    Thank you so much !!!
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    (Original post by Ethan100)
    Wowww thankss Yeah Method 2 is the way I got taught, just forgot how to do it really. I see that you took away the m from both sides, what if it gives you the mass would you substitute the number ?

    Thank you so much !!!
    In this question you are given the mass which is 3.0. However you are trying to get v on it's own and when m goes to the other side it'll just become m divided by m i.e 3/3 which cancels it out. Make sense?
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    (Original post by sameehaiqbal)
    In this question you are given the mass which is 3.0. However you are trying to get v on it's own and when m goes to the other side it'll just become m divided by m i.e 3/3 which cancels it out. Make sense?
    I think it makes sense, just need to do some questions on it

    THANKS SO MUCH sameehaiqbal
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    (Original post by Ethan100)
    I think it makes sense, just need to do some questions on it

    THANKS SO MUCH sameehaiqbal
    If you do some questions and it still doesn't make sense then just let me know!!! I will explain it again!!! I'll draw it on paper if thats what it takes lol! Don't be afraid xx
 
 
 
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