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    (Original post by adz95)
    Attachment 536057

    ...how?
    B and D, because x^2+4x+2x-x^2=6x, as 2x+4x=6x and x^2+-x^2=0
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    (Original post by Ano123)
    Any takers?
    Please explain this answer.
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    (Original post by Ano123)
    Do you not understand how to do it?
    nope, i'm doing foundation math, desperately need a C grade but can barely understand half of the questions in the past papers.
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    (Original post by chrlhyms)
    mine wasn't but my maths teacher gave me it as an A* prediction booklet for this year
    hi which prediction booklet is this?
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    (Original post by stressedoutt)
    hi which prediction booklet is this?
    im not sure! sorry my teacher just gave it to me
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    Any predictions??


    Posted from TSR Mobile
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    (Original post by hamza772000)
    Please explain this answer.
     \displaystyle \left ( \frac{2}{3} \right )^{x-1} = \left ( \left (\frac{2}{3} \right )^{-2} \right )^{x+2}
    So
     \displaystyle \left ( \frac{2}{3} \right )^{x-1} =  \left (\frac{2}{3} \right )^{-2x-4}
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    (Original post by chrlhyms)
    im not sure! sorry my teacher just gave it to me
    Okay np! ahah its okay
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    (Original post by Ano123)
     \displaystyle \left ( \frac{2}{3} \right )^{x-1} = \left ( \left (\frac{2}{3} \right )^{-2} \right )^{x+2}
    So
     \displaystyle \left ( \frac{2}{3} \right )^{x-1} =  \left (\frac{2}{3} \right )^{-2x-4}
    Ahh, now I understand, X=-1. Thanks a lot for your explanation.
    BTW, sorry for the late reply.
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    (Original post by ihatehannah)
    Make them juicy because this year they have made gcse maths much harder, i'll start us off,http://prntscr.com/b6fzjk
    Thats got to be a level
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    (Original post by ihatehannah)
    x= -1?
    how did you work this out?
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    Name:  Maths.png
Views: 65
Size:  66.2 KB
    Am I looking at this wrong or should the values I've circled be '4.505' and '4.495'??
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    (Original post by Tasha_140)
    Name:  Maths.png
Views: 65
Size:  66.2 KB
    Am I looking at this wrong or should the values I've circled be '4.505' and '4.495'??
    No the values are right I'm pretty sure
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    http://www.mathsgenie.co.uk/resources/june2016p1ans.pdf
    here's a predicted paper for tomorrow
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    (Original post by hafsa473)
    No the values are right I'm pretty sure

    But isn't the upper bound of 4.50 correct to 2d.p 4.505? And the lower bound should be 4.495?
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    (Original post by Tasha_140)
    But isn't the upper bound of 4.50 correct to 2d.p 4.505? And the lower bound should be 4.495?
    Oh wait maybe yeah
    sorry bout that it would be 4.505 and 4.495
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    http://prnt.sc/b8cw4k
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    (Original post by ihatehannah)
    Make them juicy because this year they have made gcse maths much harder, i'll start us off,http://prntscr.com/b6fzjk
    not sure if this is correct:

    http://imgur.com/KtqUF3s

    only in year 11
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     <\text{DAC} = 23^{\circ} so as the angle at the centre is double the angle at the circumference this means that  <\text{COD} = 46^{\circ} .
     <\text{PBC} = 100^{\circ} \Rightarrow <\text{ABC} = 80^{\circ} .
     <\text{ADC} = 100^{\circ} since ABCD is a quadrilateral with all vertices on the circumference of the circle and ABC is opposite angle to ADC.
    If anyone wants me to go on I can I have the full solution but it takes ages to write here.
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    (Original post by haarithiop)
    not sure if this is correct:

    http://imgur.com/KtqUF3s

    only in year 11
    It's a year 11 question.
 
 
 
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