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1. (Original post by AstarAstarA)
Geometric:
b) 256
c) 1.602

Binomial:
A = 16
k = 7/2
B = 936

Integration:
S = 24.3

Trapezium:
a) 7
b) 20.75
c) R = 5.75

Factor theorem:
a) 5
c) (x + 2)(3x + 2)(2x - 1)

Differentiation(Q10):
a) 1/3PIx^2
d) Minimum = 120m
c) x = 16.63... => f''(x) = 0.437 > 0

Trig identities:
a) Theta = 8/15Pi , -2/15Pi
b) x = 194.5, 345.5

Circle:
a) root(34)
c) 3x + 5x - 95 = 0

Log:
i) (a - 5)/9
ii) -2.19

Likely UMS:

68 - A
57 - B
49 - C
41 - D
36 - E
U
these grade boundaries are way to high
2. (Original post by civ1)
these grade boundaries are way to high
for an A id say 62-64
3. (Original post by imran_)
for an A id say 62-64
4. How many marks was the first logs question?
5. how many marks was question 8b, anyone remember ???? the log qustions
6. Can anyone explain how its 120 for the minimum value of P? I got x to be 16.7 or something close and then put that back in to the original equation to get 65m
EDIT- i think i know now, i divided the coefficient of x by 12 twice.
7. (Original post by Accountantlolks)
Would I loose any marks for not putting it in radians..??
8. (Original post by AstarAstarA)
No the last question , number one i area of the sector i put 120x instead of radians? thanks
9. (Original post by richpanda)
i got -2.19.

anyone get 9b+5 for a in terms of b?
it asked for b in terms of a. it was: b=a/9-5/9
10. (Original post by isaac_wood_)
Can anyone explain how its 120 for the minimum value of P? I got x to be 16.7 or something close and then put that back in to the original equation to get 65m
yeah, you'll only have dropped one mark for that, just put it in wrong possibly
11. (Original post by isaac_wood_)
Can anyone explain how its 120 for the minimum value of P? I got x to be 16.7 or something close and then put that back in to the original equation to get 65m
If you put 16.633... Back into the equation you got 120.something
12. (Original post by Jkylhyd)
You had to do 1944-1008 or -1008+1944 to get B as 936.
Could've sworn there wasn't any other x^2 terms. That 1944 rings a bell though. Oh well!
13. when you recognise that for the tangent question you did 10-7=2
14. (Original post by AstarAstarA)
Geometric:
b) 256
c) 1.602

Binomial:
A = 16
k = 7/2
B = 936

Integration:
S = 24.3

Trapezium:
a) 7
b) 20.75
c) R = 5.75

Factor theorem:
a) 5
c) (x + 2)(3x + 2)(2x - 1)

Differentiation(Q10):
a) 1/3PIx^2
d) Minimum = 120m
c) x = 16.63... => f''(x) = 0.437 > 0

Trig identities:
a) Theta = 8/15Pi , -2/15Pi
b) x = 194.5, 345.5

Circle:
a) root(34)
c) 3x + 5x - 95 = 0

Log:
i) (a - 5)/9
ii) -2.19

Likely UMS:

68 - A
57 - B
49 - C
41 - D
36 - E
U
The UMS is scaring me.
15. (Original post by Accountantlolks)
No the last question , number one i area of the sector i put 120x instead of radians? thanks
1/2(x^2)(120) is wrong because the area of a sector equations only work with radians. I think you have lost BOTH marks if you wrote JUST that. If you had stated the general formula and theta then you may get M1 but we're just speculating
16. (Original post by AstarAstarA)
1/2(x^2)(120) is wrong because the area of a sector equations only work with radians. I think you have lost BOTH marks if you wrote JUST that. If you had stated the general formula and theta then you may get M1 but we're just speculating
well thanjks
17. (Original post by oinkk)
Could've sworn there wasn't any other x^2 terms. That 1944 rings a bell though. Oh well!
If you multiply (1 + kx) by the x term you get another x^2 term!
18. (Original post by FakeDumbledore)
Unlucky mate I've seen the official mark scheme and a few of these are wrong :/
Better luck next year in your resit...
Does anyone have the official mark scheme?
19. (Original post by Isabellagoodwinx)
Does anyone have the official mark scheme?
The official mark scheme doesn't get released for over a year
20. (Original post by AstarAstarA)
The official mark scheme doesn't get released for over a year
That's weird because I got the c1 mark scheme the day of the exam, I don't mean the actual mark scheme I mean one a teacher has done

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