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    (Original post by bowders)
    Also did anyone get 146.5 for the mean of the apples?
    yes
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    What points did everyone plot for the 2 marks in spearmans rank (where rs = 1 but r does not equal 1)
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    (Original post by sen99)
    oh **** yeah sorry it was spearmans rank
    Haha no worries, you had to use their position on the x and y axis as ranks, so they were 12345 and 12354. I think the final answer was 0.9
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    (Original post by Breynolds2671999)
    What points did everyone plot for the 2 marks in spearmans rank (where rs = 1 but r does not equal 1)
    Did a straight line with one point higher than the rest
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    (Original post by Breynolds2671999)
    I thought it was that < 130 < or equal to 140 (or something like that)
    At 140 it is the LQ. At the LQ there is 25%.

    100% is 52 apples so 25% is 13.
    Thanks! That makes sense
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    (Original post by Ella rivers1)
    Yeah I did like probability of x greater than or equal to 2 for n as 3 and p as 0.3


    Posted from TSR Mobile
    Did you have to do it that way? I think I just used the probabilities in the table to do it
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    (Original post by h3rmit)
    I got 0.04, but 0.072 for the second one
    I got 0.04 and 0.072 as well
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    (Original post by Breynolds2671999)
    What points did everyone plot for the 2 marks in spearmans rank (where rs = 1 but r does not equal 1)
    I did it so that the points created a curved line
    • Thread Starter
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    (Original post by liverpool7867)
    For the 'abba' question:

    I think it was ((3C2 x 2C2) x (2! x 2!))/ 7C4 x 4! = 1/70

    I think that was correct
    Yeah that's what I did cause you had to pick 4 from 7 but then there were 4! Ways of arranging that 4 then finding the arrangements of ABBA and just dividing
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    (Original post by swagmister)
    I did it do that the points created a curved line
    It doesn't matter as long as the ranks were equal and it wasn't a straight line
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    (Original post by cc262626)
    Are you sure?! Loads at my school said was wrong
    It is right, I did it a weird way, but there were three ways of picking two As and two Bs, so I did 3/7C4 which was 3/35, but then out of the two As and the two Bs, there are 6 ways of arranging them so there's a 1 in 6 chance of it being in the order of ABBA. So I divided 3/35 by 6 which is 1/70, or 0.0143
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    (Original post by swagmister)
    I did it so that the points created a curved line
    I did the same
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    (Original post by Breynolds2671999)
    What points did everyone plot for the 2 marks in spearmans rank (where rs = 1 but r does not equal 1)
    a curve
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    can we make a markscheme? on here or a goole docs? just so we can see it all laid out
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    (Original post by Breynolds2671999)
    What points did everyone plot for the 2 marks in spearmans rank (where rs = 1 but r does not equal 1)
    A zigzag which has a positive correlation, means r not 1 but rs still=1
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    Let's do another community MS. Please press the button to request permission to contribute.
    https://docs.google.com/document/d/1...it?usp=sharing
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    wat was the second past of question 1?
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    How did you work out mean of z?
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    45 marks for an A.
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    (Original post by Btec certified)
    45 marks for an A.
    I wish , probably about 56 or 57
 
 
 
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