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    (Original post by DaVinciGirl)
    I wrote they have a high bond enthalpy.
    I said the CO bond is polar and there are dipoles so radiation can be absorbed lol
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    (Original post by rosemondtan)
    I said the CO bond is polar and there are dipoles so radiation can be absorbed lol
    It could be right, I tried checking all my textbooks and didn't manage to find an answer
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    (Original post by liziepie)
    Wouldn't heat loss to apparatus still count as heat loss to enviroment? I thought it might be because data book value uses mean bond enthalpy, but not sure for that one ...
    I also thought the same in the exam because I recall that the data book uses mean bond enthalpy. But they didn't state explicitly so I just tried remembering another reason. I said that they didn't consider the specific heat capacity of copper in the calculation
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    Na m8 there's always two nitrous oxide
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    (Original post by rosemondtan)
    Just asked my physics and chem teacher just now and it's 1.31% for the uncertainty!
    That's a relief. Thank you!
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    (Original post by DaVinciGirl)
    It could be right, I tried checking all my textbooks and didn't manage to find an answer
    Im thinking its something to do with IR is a certain frequency and bonds like O-H and C=C can absorb those certain frequencies

    Also
    Was Maxwell Boltsman D?
    And I only guessed 1 about the 5H20 compound was it B by any chance?
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    (Original post by DaVinciGirl)
    That's a relief. Thank you!
    How do you think you did in paper 1?

    Thanks for making these mark schemes btw!
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    (Original post by DaVinciGirl)
    I also thought the same in the exam because I recall that the data book uses mean bond enthalpy. But they didn't state explicitly so I just tried remembering another reason. I said that they didn't consider the specific heat capacity of copper in the calculation
    It's evaporation or container absorbs some heat
    I put the copper container
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    (Original post by rosemondtan)
    I said the CO bond is polar and there are dipoles so radiation can be absorbed lol
    Oh my God your so awesome I writ that tooo I was like it's polar and c has a s+ and I had s- so happy.

    Btw in the multiple choose did you guys see the mistake for the bond enthalpy question where it printed c triple bond o instead of c double bond o
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    (Original post by Enderbat1999)
    Oh my God your so awesome I writ that tooo I was like it's polar and c has a s+ and I had s- so happy.

    Btw in the multiple choose did you guys see the mistake for the bond enthalpy question where it printed c triple bond o instead of c double bond o
    It was there because the reactants had a carbon monoxide I think.

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    (Original post by DaVinciGirl)
    That's a relief. Thank you!
    I wrote mine to 3 Sig figures but did do 0.5/38x100

    So I wrote 1.32 will I still get the mark
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    (Original post by DaVinciGirl)
    It was there because the reactants had a carbon monoxide I think.

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    Oh ok btw the markscheme you put up for that 6 marker is wrongs I think and a few other s agree cus

    It is the oh group first so the alcohol
    Then is is thebutane cus van Der waals and greater Mr

    Then the aldehyde one as it was polar and only had 3 carbon so dipole dipole and much less can Der waals I checked with my teacher she said it was right
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    (Original post by SANTR)
    How do you think you did in paper 1?

    Thanks for making these mark schemes btw!
    Thank you for appreciating it!
    Honestly I did not do as well in paper 1, that's because my time limit was terribly bad and I improved on this paper. Hopefully it's still an A but I did do some stupid mistakes. I actually record all marks I think I got for each exam to prepare me for results day lol. In this one I think I got 13 marks wrong and the first paper 18 marks wrong I really want an A lol
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    (Original post by liziepie)
    Wouldn't heat loss to apparatus still count as heat loss to enviroment? I thought it might be because data book value uses mean bond enthalpy, but not sure for that one ...
    this is exactly what i wrote and im 99% sure it was what they were looking for
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    (Original post by DaVinciGirl)
    Sorry about the misunderstanding, I reworded the sentence
    DW haha. Just clearing something up with them ^
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    (Original post by river222)
    Im thinking its something to do with IR is a certain frequency and bonds like O-H and C=C can absorb those certain frequencies

    Also
    Was Maxwell Boltsman D?
    And I only guessed 1 about the 5H20 compound was it B by any chance?
    I believe the Maxwell is C and I'm not sure which question you are referring to with the 5H2O?
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    (Original post by Splaffie)
    this is exactly what i wrote and im 99% sure it was what they were looking for
    I'll check the mark scheme for the old papers and see what they usually look for
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    (Original post by Enderbat1999)
    Oh ok btw the markscheme you put up for that 6 marker is wrongs I think and a few other s agree cus

    It is the oh group first so the alcohol
    Then is is thebutane cus van Der waals and greater Mr

    Then the aldehyde one as it was polar and only had 3 carbon so dipole dipole and much less can Der waals I checked with my teacher she said it was right
    But isn't van der waals really the weakest intermolecular force that brings quite easily? Wouldn't permanent dipole dipole overcome the van der waals forces. Not sure tho. Doesn't the alkane only have one extra carbon?
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    (Original post by liziepie)
    Wouldn't heat loss to apparatus still count as heat loss to enviroment? I thought it might be because data book value uses mean bond enthalpy, but not sure for that one ...
    I thought for that question it only had dont include heat transfer? I dont remember the enviroment part, but the mean bond enthalpy is a mark and if it said to the enviroment then apparatus would be correct because the apparatus isn't a gas.
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    (Original post by Enderbat1999)
    Oh ok btw the markscheme you put up for that 6 marker is wrongs I think and a few other s agree cus

    It is the oh group first so the alcohol
    Then is is thebutane cus van Der waals and greater Mr

    Then the aldehyde one as it was polar and only had 3 carbon so dipole dipole and much less can Der waals I checked with my teacher she said it was right
    I just googled it and it said the same as what I wrote.
    I even searched both of their boiling points.
 
 
 
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