Uh oh...(Original post by trentjoseph007)
JUST TO GET PEOPLES ATTENTION !!!
I think everyone misunderstood the last question on the paper. It was white light passing through a single slit. Look at the textbook page 202, figure 2. Apparently no one here realized it.
You are Here:
Home
> Forums
>< Study Help
>< Maths, science and technology academic help
>< Physics
>< Physics Exams

The Physics PHYA2 thread! 5th June 2013 Watch
Announcements

View Poll Results: What mark do you think you got out of 70?02063.00%2140126.00%41502914.50%51607939.50%61707437.00%Voters: 200. You may not vote on this poll

 Follow
 1781
 05062013 15:09

 Follow
 1782
 05062013 15:09
The Unofficial Mark scheme People.. thanks to Lebron! can everyone please find what's missing and where the last question goes so we can properly estimate what we got. Thanks
(Original post by lebron_23)
PHYA1 (Provisional, and very shaky) Mark scheme;
Question 1 – Simple matter of working out forces and that stuff, efficiency question may cause problems though.
1) 6082N, which is 6100 to 2sf (2)
b) 9.5 degrees using arctan of 1000/6000 (2)
c) Acceleration was 9.2ms^2 (2)
d) Can’t remember what this one was asking but I got 3.9x10^6 (not sure) (2)
e) I got 20.5% but I’m not sure as I’ve heard people give various answers (3)
Question 2 – Fairly straightforward question about projectiles.
2) Time taken was 0.55s (2)
b) The horizontal distance was 248m I think (2)
c) As both bullets have the same mass, S=ut will be smaller for the bullet with the lower horizontal velocity (3?)
 Can’t remember if there was anything more to this question
Question 3 – Perhaps the best 6 marker they’ve ever given, very straightforward.
3) The ball begins to accelerate with a large acceleration as its weight force is (one of) the only forces acting as it begins to move. The gradient then begins to slowly decrease as the resistive forces begin to balance out the weight force. The ball finally reaches terminal velocity as the resistive forces balance out the weight force. Appropriate reference to Newton’s first law needed. Then the ball remains at that velocity, as there is no external force, give reference to Second Law. (6)
b) Initially a straight line indicating uniform acceleration, then a curve of decreasing gradient ending with the ball at terminal velocity. (3)
Question 4 – A decent question, I guess.
4) Weight of the ball was 0.44N (2sf) using volume of a sphere which is given in the data sheet!!! (4)
b)Hooke’s law states that force applied is proportional to the extension up to the limit of proportionality (2)
c) Gradient was roughly 1150/1100 Nm^1needed (3)
d) Using the area of a triangle and then counting (roughly) 9 small boxes each of area 0.025 gave 1.08J (3?)
e) Straight line parallel to the first one but not finishing at zero as plastic deformation has occurred (2)
d) Plastic deformation means the object won’t return to its original shape/length once the load is removed (2)
f) Work is less as area under graph is less energy absorbed as heat and in permanent extension (1)
Question 5 – Wasn’t too bad..
5) Two conditions for TIR were an angle greater than the critical angle and moving from a medium of higher refractive index to lower (2)
b) Defining the frequency of a progressive wave. Just explain the equation? (1)
c) Speed of light in the object thing was 1.7x10^8 (2)
d) Proof that the angle was about 31.8 degrees using Snell’s Law
e) Critical angle was 51.1 degrees using 1/sinc (2)
f) Undergoes TIR as (20+31.9) > 51 (2)
e) TIR drawn (not sure about this one and the one above) (1)
Question 6 – Don’t even know, seemed cool..
6) First phase difference was 90 degrees or pi/2. Second was 270 degrees or 3pi/2 (2)
b) Oscillation between maximum and minimum amplitude; i.e moves up and down (2)
c) Polarisation only occurs in transverse waves; mention something about plane of polarisation (2)
d) Define frequency (1)
e) 750m (2)
Question 7 – I may have flopped
7) All of the light has the same wavelength (1)
b) Can’t really remember – According to Frogs491 its ‘Fringes larger so intensity equal’  If this is the graph of intensity, then (2)
c) I too cannot seem to remember this
e) Last part; white at central maxima and very bright as all of the wavelengths converge at the centre; blue tinge closer to central maxima and red tinge further away; not sure about anything else. (3)
That’s all I can remember guys. I’ve probably omitted quite a few things so if anyone can spot any mistakes, let me know and I’ll make amendments
EDIT: I'm going to start adding in the marks for each question slowly so that should be half done soon. If anyone can remember what the marks are for each question please let me know! Thanks.
Also, I can't remember where the question about the weight of the ball goes but it was 0.44N and worth (4) marks...
Guys, we're missing 4 marks so if anyone can remember anything... 
 Follow
 1783
 05062013 15:10
Feel like poo. Rushed through and didn't see that they'd already given the speed of the light ray. For some reason I used the speed in a stupid vacuum :'(

Aarongreatbanks
 Follow
 0 followers
 0 badges
 Send a private message to Aarongreatbanks
Offline0ReputationRep: Follow
 1784
 05062013 15:12
My mark scheme
1a) square root of 1000 squared+ 6000 squared
1b) 32
1c) 9.2
1d) 3900000
1e) 22%
2a)0.55
2b) 240
2c) the horizontal displacement =ut. It takes the same time to falls and u is less and therefore the distance travelled is less
3a)
Inital quick acceleration shown by steep gradient
As it falls a drag force is produced
As the object falls the drag force on it increases reducing the resultant force
F=ma with respect to Newton's second law and so the acceleration decreases as it falls as shown by the gradient getting smaller
Eventually drag is equal and opposite to weight
Ball travels at constant Velocity shown by the straight part of the graph near the end of time
Reference to Newton's first law as it moves at a constant velocity as there is no resultant force
Some of the energy of the object is converted into internal energy of the oil
It finally hits the bottom as shown by the vertical line at the end
3b) I did a striaght line to about 3/4 the way up the line before it hit the fluid
Copied the graph from the page before for the second bit but starter it lower to show it's speed falls when it hits the oil
Striaght line at the end
4a) I got the wrong as I said f *proportional sign* KL and defined the terms
4b) 1200 n/m
4c) 9.4? I got this wrong I think I found how many squares there were and times by the area per square
4d) the object is permanently stretched and doesn't return to its inital length
4e) striaght line to the x axis but a bit to the right than the first list as there is extension at the end of unloading
4d) more work required when loading
5a) n1>n2
Angle of incidence>critical angle
5b) 51
5c) 30
5d) it totally internally reflects as angle of incidence is more than critical angle
5e) reflects away at same angle
6a) 90 out of phase
270 out of phase
6b) up, down to equilibrium, down again, back up to equilibrium
6c) it's transverse as longitudinal can't be polarised
6d)1.7 x10 to the 8
6e) 750
6f) was there any more questions here?
7a) light consists of a single wavelength
7b) lower intensity, wider fringes
7c) don't shine it into people's face or look along the beam as it will damage the eye
7d) central white maximum, subsidiary maxima consisting of spectra with blue on inside and red on outside of the fringes. The intensity is less than laser light.
I think I got 54/70 maybe. As I've taken time to create this could you give me yor opinions on my score? 
Aarongreatbanks
 Follow
 0 followers
 0 badges
 Send a private message to Aarongreatbanks
Offline0ReputationRep: Follow
 1785
 05062013 15:16
(Original post by waheed786)
The Unofficial Mark scheme People.. thanks to Lebron! can everyone please find what's missing and where the last question goes so we can properly estimate what we got. Thanks
My mark scheme
1a) square root of 1000 squared+ 6000 squared
1b) 32
1c) 9.2
1d) 3900000
1e) 22%
2a)0.55
2b) 240
2c) the horizontal displacement =ut. It takes the same time to falls and u is less and therefore the distance travelled is less
3a)
Inital quick acceleration shown by steep gradient
As it falls a drag force is produced
As the object falls the drag force on it increases reducing the resultant force
F=ma with respect to Newton's second law and so the acceleration decreases as it falls as shown by the gradient getting smaller
Eventually drag is equal and opposite to weight
Ball travels at constant Velocity shown by the straight part of the graph near the end of time
Reference to Newton's first law as it moves at a constant velocity as there is no resultant force
Some of the energy of the object is converted into internal energy of the oil
It finally hits the bottom as shown by the vertical line at the end
3b) I did a striaght line to about 3/4 the way up the line before it hit the fluid
Copied the graph from the page before for the second bit but starter it lower to show it's speed falls when it hits the oil
Striaght line at the end
4a) I got the wrong as I said f *proportional sign* KL and defined the terms
4b) 1200 n/m
4c) 9.4? I got this wrong I think I found how many squares there were and times by the area per square
4d) the object is permanently stretched and doesn't return to its inital length
4e) striaght line to the x axis but a bit to the right than the first list as there is extension at the end of unloading
4d) more work required when loading
5a) n1>n2
Angle of incidence>critical angle
5b) 51
5c) 30
5d) it totally internally reflects as angle of incidence is more than critical angle
5e) reflects away at same angle
6a) 90 out of phase
270 out of phase
6b) up, down to equilibrium, down again, back up to equilibrium
6c) it's transverse as longitudinal can't be polarised
6d)1.7 x10 to the 8
6e) 750
6f) was there any more questions here?
7a) light consists of a single wavelength
7b) lower intensity, wider fringes
7c) don't shine it into people's face or look along the beam as it will damage the eye
7d) central white maximum, subsidiary maxima consisting of spectra with blue on inside and red on outside of the fringes. The intensity is less than laser light.
I think I got 54/70 maybe. As I've taken time to create this could you give me yor opinions on my score? 
AngryAsamoah
 Follow
 0 followers
 0 badges
 Send a private message to AngryAsamoah
Offline0ReputationRep: Follow
 1786
 05062013 15:17
can anyone remember how many marks the last question was worth?

xSophiex
 Follow
 17 followers
 13 badges
 Send a private message to xSophiex
Offline13ReputationRep: Follow
 1787
 05062013 15:18
(Original post by trentjoseph007)
JUST TO GET PEOPLES ATTENTION !!!
I think everyone misunderstood the last question on the paper. It was white light passing through a single slit. Look at the textbook page 202, figure 2. Apparently no one here realized it.
EDIT: It wasn't a easy question.
Posted from TSR Mobile 
 Follow
 1788
 05062013 15:22
Goodness me! Reckon I've got 55.. I wanted full UMS but that's not happening.. :l

.raiden.
 Follow
 17 followers
 1 badge
 Send a private message to .raiden.
 Thread Starter
Offline1ReputationRep: Follow
 1789
 05062013 15:22
(Original post by Aarongreatbanks)
I got this maybe take the good bits from mine if there are any and add to yours? Also what do you think I would get /70 I'd greatly appreciate it if someone gave me their scores
My mark scheme
1a) square root of 1000 squared+ 6000 squared
1b) 32
1c) 9.2
1d) 3900000
1e) 22%
2a)0.55
2b) 240
2c) the horizontal displacement =ut. It takes the same time to falls and u is less and therefore the distance travelled is less
3a)
Inital quick acceleration shown by steep gradient
As it falls a drag force is produced
As the object falls the drag force on it increases reducing the resultant force
F=ma with respect to Newton's second law and so the acceleration decreases as it falls as shown by the gradient getting smaller
Eventually drag is equal and opposite to weight
Ball travels at constant Velocity shown by the straight part of the graph near the end of time
Reference to Newton's first law as it moves at a constant velocity as there is no resultant force
Some of the energy of the object is converted into internal energy of the oil
It finally hits the bottom as shown by the vertical line at the end
3b) I did a striaght line to about 3/4 the way up the line before it hit the fluid
Copied the graph from the page before for the second bit but starter it lower to show it's speed falls when it hits the oil
Striaght line at the end
4a) I got the wrong as I said f *proportional sign* KL and defined the terms
4b) 1200 n/m
4c) 9.4? I got this wrong I think I found how many squares there were and times by the area per square
4d) the object is permanently stretched and doesn't return to its inital length
4e) striaght line to the x axis but a bit to the right than the first list as there is extension at the end of unloading
4d) more work required when loading
5a) n1>n2
Angle of incidence>critical angle
5b) 51
5c) 30
5d) it totally internally reflects as angle of incidence is more than critical angle
5e) reflects away at same angle
6a) 90 out of phase
270 out of phase
6b) up, down to equilibrium, down again, back up to equilibrium
6c) it's transverse as longitudinal can't be polarised
6d)1.7 x10 to the 8
6e) 750
6f) was there any more questions here?
7a) light consists of a single wavelength
7b) lower intensity, wider fringes
7c) don't shine it into people's face or look along the beam as it will damage the eye
7d) central white maximum, subsidiary maxima consisting of spectra with blue on inside and red on outside of the fringes. The intensity is less than laser light.
I think I got 54/70 maybe. As I've taken time to create this could you give me yor opinions on my score? 
xSophiex
 Follow
 17 followers
 13 badges
 Send a private message to xSophiex
Offline13ReputationRep: Follow
 1790
 05062013 15:22
(Original post by AngryAsamoah)
can anyone remember how many marks the last question was worth?
Posted from TSR Mobile 
 Follow
 1791
 05062013 15:22
(Original post by Aarongreatbanks)
My mark scheme
1a) square root of 1000 squared+ 6000 squared
1b) 32
1c) 9.2
1d) 3900000
1e) 22%
2a)0.55
2b) 240
2c) the horizontal displacement =ut. It takes the same time to falls and u is less and therefore the distance travelled is less
3a)
Inital quick acceleration shown by steep gradient
As it falls a drag force is produced
As the object falls the drag force on it increases reducing the resultant force
F=ma with respect to Newton's second law and so the acceleration decreases as it falls as shown by the gradient getting smaller
Eventually drag is equal and opposite to weight
Ball travels at constant Velocity shown by the straight part of the graph near the end of time
Reference to Newton's first law as it moves at a constant velocity as there is no resultant force
Some of the energy of the object is converted into internal energy of the oil
It finally hits the bottom as shown by the vertical line at the end
3b) I did a striaght line to about 3/4 the way up the line before it hit the fluid
Copied the graph from the page before for the second bit but starter it lower to show it's speed falls when it hits the oil
Striaght line at the end
4a) I got the wrong as I said f *proportional sign* KL and defined the terms
4b) 1200 n/m
4c) 9.4? I got this wrong I think I found how many squares there were and times by the area per square
4d) the object is permanently stretched and doesn't return to its inital length
4e) striaght line to the x axis but a bit to the right than the first list as there is extension at the end of unloading
4d) more work required when loading
5a) n1>n2
Angle of incidence>critical angle
5b) 51
5c) 30
5d) it totally internally reflects as angle of incidence is more than critical angle
5e) reflects away at same angle
6a) 90 out of phase
270 out of phase
6b) up, down to equilibrium, down again, back up to equilibrium
6c) it's transverse as longitudinal can't be polarised
6d)1.7 x10 to the 8
6e) 750
6f) was there any more questions here?
7a) light consists of a single wavelength
7b) lower intensity, wider fringes
7c) don't shine it into people's face or look along the beam as it will damage the eye
7d) central white maximum, subsidiary maxima consisting of spectra with blue on inside and red on outside of the fringes. The intensity is less than laser light.
I think I got 54/70 maybe. As I've taken time to create this could you give me yor opinions on my score? 
trentjoseph007
 Follow
 0 followers
 0 badges
 Send a private message to trentjoseph007
Offline0ReputationRep: Follow
 1792
 05062013 15:24

 Follow
 1793
 05062013 15:24
Does anyone remember what was the question to... "5c) Speed of light in the object thing was1.7x10^8"

 Follow
 1794
 05062013 15:26
(Original post by waheed786)
Does anyone remember what was the question to... "5c) Speed of light in the object thing was1.7x10^8" 
Aarongreatbanks
 Follow
 0 followers
 0 badges
 Send a private message to Aarongreatbanks
Offline0ReputationRep: Follow
 1795
 05062013 15:27
(Original post by tmister)
I think you got about 35 with those answers. Well done 
 Follow
 1796
 05062013 15:28
(Original post by waheed786)
Does anyone remember what was the question to... "5c) Speed of light in the object thing was1.7x10^8" 
 Follow
 1797
 05062013 15:31
(Original post by Aarongreatbanks)
I think I got at least 50? How the hell did you get 35 
Aarongreatbanks
 Follow
 0 followers
 0 badges
 Send a private message to Aarongreatbanks
Offline0ReputationRep: Follow
 1798
 05062013 15:32
(Original post by tmister)
I think some of the maths answers you gave are wrong i.e 1b, if I was you I'd fill out the resit form now and get in front of the queue. Better luck next time mate!!!! 
masryboy94
 Follow
 6 followers
 2 badges
 Send a private message to masryboy94
Offline2ReputationRep: Follow
 1799
 05062013 15:35
(Original post by .raiden.)
5e) I don't think total internal reflection occurs?Last edited by masryboy94; 05062013 at 15:37. 
.raiden.
 Follow
 17 followers
 1 badge
 Send a private message to .raiden.
 Thread Starter
Offline1ReputationRep: Follow
 1800
 05062013 15:36
(Original post by masryboy94)
i agree, it does not happen, because between glass A and B it does since n_{1 }^ n_{2 }and exceed its critical angle fo but when we worked out the critical angle r that section which we could work out to be 60 degrees since we have the angle of refraction from air to A. and by simply adding angles, you could find out at what angle it hit the boundary from A to C (which was less than the critical angle calculated hence it refracts and not T.I.R
Reply
Submit reply
Related discussions:
 AQA PHYSICS UNIT2 (PHYA2) June 5th 2013
 AQA Physics PHYA5  Thursday 18th June 2015 [Exam ...
 AQA Physics PHYA4  Thursday 11th June 2015 [Exam ...
 AQA Physics A Unit 4 11 June 2014
 Aqa chem 4/ chem 5 june 2016 thread
 The "Are my grades good enough for Maths..." Thread
 AS Level Results Day Thread  14/08/14
 The "Are my grades good enough for Maths..." Thread
 The Official Cambridge Applicants Thread 2016 Entry MK II
 As/A Level Results Day 2013  9 DAYS REMAINING
TSR Support Team
We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.
This forum is supported by:
 charco
 Mr M
 TSR Moderator
 Nirgilis
 usycool1
 Changing Skies
 James A
 rayquaza17
 Notnek
 RDKGames
 randdom
 davros
 Gingerbread101
 Kvothe the Arcane
 The Financier
 The Empire Odyssey
 Protostar
 TheConfusedMedic
 nisha.sri
 Reality Check
 claireestelle
 Doonesbury
 furryface12
 Amefish
 harryleavey
 Lemur14
 brainzistheword
 Rexar
 Sonechka
 LeCroissant
 EstelOfTheEyrie
 CoffeeAndPolitics
 an_atheist
 Moltenmo
Updated: September 15, 2013
Share this discussion:
Tweet