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# Mega A Level Maths Thread MK II Watch

1. (Original post by thers)
This has got to be the worst a level maths question I have seen lmfao. I scored 1/14 on it.

http://filestore.aqa.org.uk/subjects...2-QP-JAN12.PDF

Question 8. I can't make any progress past part (a). Can anyone explain what to do at all?
The pdf looks little weird tbh.

Does ?
2. (Original post by thers)
This has got to be the worst a level maths question I have seen lmfao. I scored 1/14 on it.

http://filestore.aqa.org.uk/subjects...2-QP-JAN12.PDF

Question 8. I can't make any progress past part (a). Can anyone explain what to do at all?
I've not actually checked, but I imagine that the roots of are the same as the roots of
given that it says hence
3. (Original post by joostan)
I've not actually checked, but I imagine that the roots of are the same as the roots of
given that it says hence
They are apparently but why?
4. (Original post by thers)
They are apparently but why?
Because
5. (Original post by justinawe)
No.

, using basic log rules.

So definitely not the same thing.
Yeah silly me

Thanks a lot
6. (Original post by joostan)
Because
Right, do you have any ideas for the next 2 parts?
7. (Original post by joostan)
Because
Actually I've figured out how to do (d) by using the given answer in (c). But can't do (c)
8. (Original post by thers)
Right, do you have any ideas for the next 2 parts?
You know (by de Moivre) that How does this help, do you think?
9. Lost 3 marks on Jan 2013 on this...

I think I know why, but the mark scheme has no workings, just the values

Do I work out the gradient and make it negative to find a?
10. M5, June 2009. 99 UMS.

This is what my life has become.
11. (Original post by joostan)
You know (by de Moivre) that How does this help, do you think?
So I've got z^2 + z^-2 + 2cos2pi/5 + 1 = 0
What next?
12. (Original post by DJMayes)
M5, June 2009. 99 UMS.

This is what my life has become.
Arithmetic errors?
13. (Original post by L'Evil Fish)
Lost 3 marks on Jan 2013 on this...

I think I know why, but the mark scheme has no workings, just the values

Do I work out the gradient and make it negative to find a?
Yep
14. (Original post by joostan)
Yep
Darn it!

Lets hope I can smash Friday's exam now lets see what UMS I'd have had..

2012: 100 UMS
2013: 97 UMS

I want 97 (birth year )
15. (Original post by thers)
So I've got z^2 + z^-2 + 2cos2pi/5 + 1 = 0
What next?
What you're trying to do is factorise the quartic into 2 quadratics, then divide by z^2 to get the desired result
16. (Original post by L'Evil Fish)
Darn it!

Lets hope I can smash Friday's exam now lets see what UMS I'd have had..

2012: 100 UMS
2013: 97 UMS

I want 97 (birth year )
100 is a bit showy - same goes for you DJ
17. (Original post by joostan)
100 is a bit showy - same goes for you DJ
Showy? I want 97/98... So it looks nice... I'd love a 100 though, in one of C3/4 but not gonna happen
18. (Original post by Boy_wonder_95)
Arithmetic errors?
Not even arithmetic, even worse. On a vectors question on systems of forces I forgot to multiply by -1 so forces would cancel out, -2 accuracy marks. Then, on a moments of inertia question with finding the force on a hinge, an absolute monster worth 9 marks, I did it all completely correctly, managed to avoid the 1001 different places I could have made an arithmetical error, but forgot to add an mg on the end of 1 of two things when expanding them out from brackets in the final line, so minus another mark.
19. (Original post by joostan)
What you're trying to do is factorise the quartic into 2 quadratics, then divide by z^2 to get the desired result
Right so I've got a quartic

z^4 + (2cos(2pi/5) + 1 )z^2 + 1 =0

How am I supposed to factorize this?
20. (Original post by thers)
Right so I've got a quartic

z^4 + (2cos(2pi/5) + 1 )z^2 + 1 =0

How am I supposed to factorize this?
Well you know the linear factors, you multiply two linear dactors together and you get a quadratic, you just need to pick which linear factors you want to mulitply to get the desired result.

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