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    (Original post by oinkk)
    My thoughts: dreadful. I'm usually confident after exams, but this was just so unlike an FP2 paper.

    1. Inequalities: standard
    2. Series: really difficult to spot the method to sum the terms that didn't cancel. I didn't reach the required answer.
    3. Complex roots: standard
    4. First-order: completely messed it up. The change in variable confused me greatly, and didn't spot the easiest integrating factor ever in part b). Ended up with an integrating factor of 1/(cosec theta + cot theta)^2
    5. Taylor series: standard. Worded a bit weirdly, but otherwise nothing away from the norm.
    6. Second-order: tricky to do the transformation. Has came up many times recently and I got confused with my chain rule. But otherwise standard once you get the ball rolling.
    7. de Moivres: standard
    8. Polar coordinates: was a little confused by the decimal limit. If you've done past papers you would've spotted that you needed the area of the sector, then integrate curve C1.

    I knew Edexcel would've doubled-down on FP2 given the past few papers have been relatively easy (64-67 for an A).

    I think the grade boundaries will be:
    A*: 59
    A: 55
    B: 49
    U high brah? I'd advise you not to give people false hope. Those are way too low and we both know that.
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    (Original post by geniuses)
    Guys Morgan Sachs is hiring.


    Just accepted my application. I will be using suvat equations to calculate at what acceleration the cash register opens.
    Who says the cash register opens at a constant acceleration?
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    So what was the final answer to Q4 part (ii) (7 marks)?
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    (Original post by cjlh)
    For Q8:
    Does 2 * [(region C1 from 0 to arrcos(3/4)) + (region C2 from arccos(3/4) to pi/2)] sound valid?
    This is what I did but I got a different answer to most people :/ (got area as 71.00)
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    (Original post by Pyslocke)
    Oh god I hope you're right about those grade boundaries. But I will keep my expectations high and assume it will be around 66 for A*. 60 for an A.
    (Original post by oinkk)
    My thoughts: dreadful. I'm usually confident after exams, but this was just so unlike an FP2 paper.

    1. Inequalities: standard
    2. Series: really difficult to spot the method to sum the terms that didn't cancel. I didn't reach the required answer.
    3. Complex roots: standard
    4. First-order: completely messed it up. The change in variable confused me greatly, and didn't spot the easiest integrating factor ever in part b). Ended up with an integrating factor of 1/(cosec theta + cot theta)^2
    5. Taylor series: standard. Worded a bit weirdly, but otherwise nothing away from the norm.
    6. Second-order: tricky to do the transformation. Has came up many times recently and I got confused with my chain rule. But otherwise standard once you get the ball rolling.
    7. de Moivres: standard
    8. Polar coordinates: was a little confused by the decimal limit. If you've done past papers you would've spotted that you needed the area of the sector, then integrate curve C1.

    I knew Edexcel would've doubled-down on FP2 given the past few papers have been relatively easy (64-67 for an A).

    I think the grade boundaries will be:
    A*: 59
    A: 55
    B: 49
    Sorry to burst the bubble but those will definitely not be the boundaries.
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    (Original post by Euclidean)
    What numerical answer did people get for the last part of Q8? I got 63.4 or something but now I think I messed up the numbers somewhere.
    Me too 😂😂
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    (Original post by Inges)
    Terrible. Anybody got any Idea when a model mark scheme may be available?
    Will release one tomorrow.
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    So I've confused myself on redoing part b of the polar co-ordinates question.

    I did this, and I'm struggling to see why I only got 15 rather than 35. Surely this gives the required area?

    2.\frac{1}{2}\int_{0.722}^{\frac  {\pi}{2}}(7cos\theta )^2 + \frac{(2 * 0.722)}{2\pi}*(r)^2

    First part evaluates to 8.64 and the second part evaluates to 6.33, giving a total of ~15?
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    Sooooooooo.......Am I the only one that got a (dy/du)^2 on the substitution question and then didn't know what to do....and then almost had a panic attack......and then never looked at that question again......and then got home to see nobody on tsr had the same problem??? Just me? I'll cry on my own then
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    (Original post by NamelessPersona)
    This is what I did but I got a different answer to most people :/ (got area as 71.00)
    I'm not entirely sure if I got 30.5, but I def didn't get 71. You didn't half the integrals I'm guessing?
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    (Original post by embem10)
    Yeah I was so confused?
    Glad I wasn't the only one


    Posted from TSR Mobile
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    (Original post by PhyM23)
    Who says the cash register opens at a constant acceleration?
    ****, I'm useless with my M1 in that case.

    Will probably become a therapist then helping other traumatised M1 students.
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    (Original post by oinkk)
    I think the grade boundaries will be:
    A*: 59
    A: 55
    B: 49
    I know it wasn't a very easy paper but that's being overly optimistic. Sorry!
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    (Original post by physics_maths7)
    Sooooooooo.......Am I the only one that got a (dy/du)^2 on the substitution question and then didn't know what to do....and then almost had a panic attack......and then never looked at that question again......and then got home to see nobody on tsr had the same problem??? Just me? I'll cry on my own then
    You get dy/du but the squared I got was of (du/dx). You know du/dx is 1/x so this is 1/x^2 (which you then substitute in).
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    Initial reactions show people either found it quite hard, or quite easy.I'm still sticking by my prediction of 67 for A* (maybe 66, if we consider reactions on other networks such as Twitter)

    Don't forget to vote!
    http://www.thestudentroom.co.uk/show....php?t=4150121
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    Is there a link to the actual paper?
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    (Original post by cjlh)
    I'm not entirely sure if I got 30.5, but I def didn't get 71. You didn't half the integrals I'm guessing?
    I think I said as it is 2 times half the integral of r^2 for both I just put the sum of the two integrals. Maybe I shouldn't have done that.
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    (Original post by NamelessPersona)
    I think I said as it is 2 times half the integral of r^2 for both I just put the sum of the two integrals. Maybe I shouldn't have done that.
    That's what I did as well, that's the way to do it I think. May have messed up the numbers or typed it wrong?
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    (Original post by cjlh)
    That's what I did as well, that's the way to do it I think. May have messed up the numbers or typed it wrong?
    Possibly, in which case I am hoping for the method marks. I estimate I got anywhere from 60 - 67 ish depending on leniency.
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    Guys what did you get for the area of the polar curves? I got 71.0 or 49pi/2 + (3root7)/4 -11arccos3/4
 
 
 
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