The Student Room Group

OCR A2 CHEMISTRY F324 and F325- 14th and 22nd June 2016- OFFICIAL THREAD

Scroll to see replies

for the equation of the reduction of the aldehyde to alcohol, would putting OH- as a second product be fine?
so is it ethanoic acid or propanoic acid?
Original post by KB_97
The unofficial make scheme Google document is a hot mess. I'm gonna put what I got the last structures on here. If you got the same as me thumbs up if not say what you got and we'll see who agrees/disagrees

New unofficial mark scheme document

Only selected users can edit, everybody can comment.

https://goo.gl/gEi388
(edited 7 years ago)
Original post by lanah_
Is there an unofficial mark scheme?


https://titanpad.com/n3swQKWGYk
100% sure the NMR thing was doublet doublet quartet
Original post by adnan_ja01
for the equation of the reduction of the aldehyde to alcohol, would putting OH- as a second product be fine?


Pretty sure the only acceptable form would be:

Aldehyde + 2[o] --> alcohol
Why did the secondary alcohol and ketone have a ch3 group off it? Why couldn't it be a straight chain?
Original post by jadder1224
1465919140947-1446831368.jpg did anyone get these ?


Does it have to have the methyl?! I just did it as straight pentanone :/
Original post by FluffyCommie
Pretty sure the only acceptable form would be:

Aldehyde + 2[o] --> alcohol


You mean 1 O right?
Original post by gonecrazy
so is it ethanoic acid or propanoic acid?


it's definitely propanoic acid
Original post by CharleaM
I got the Mr as 74 hence proanoic acid


Yeah, everyone else says 74,
I somehow got the number '60' as Mr which is a Mr for ethanoic acid funny enough so I thought I leave the answer there.
Yeah, you all probably right, Mr is 74
Original post by A Slice of Pi
Did you also state the number of possible isomers (2)? They wanted to see the actual number of possibilities in the Jun15 paper.


Only because in June 2015 they specifically talked about 25% of the dose being effective (hence four optical isomers).
Original post by jamesgates1
Why did the secondary alcohol and ketone have a ch3 group off it? Why couldn't it be a straight chain?


thats what I did im so confused, it didn't say it was branched or anything either
What I remember (there may be mistakes)

octadec-9,12-enoic acid because it has two trans isomers? which increases level of bad cholesterol.

Cis-trans isomerism requires different groups attached to each carbon in c=c bond.

Alcohol and amide.functional groups

condensation polymer was polyamide and used as fibres in clothing

Measure Rf values and compare with known Rf values. 2 spots instead of 3 because compounds may not have separated fully

Polylactic acid could breakdown because ester linkages could be hydrolyses and the stitches could be dissolved because lactic acid could form hydrogen bonds with water using its OH groups.

Diester made of six carbons and two ester bonds (skeletal formula)
Percentage yield mass = 2.66g

formula for peak A was just molecular formula with positive charge
peak B was CH3CH2NH2 (or something like that) and positive charge

work out mr of Compound H Mr - 74.
Compound H: CH3CH2COOH
For Compound J: (CH3)3CH2OH
Original post by President J
It was all under 2 I thought. As it was a 3 Carbons. Doublet, Doublet, Multiplet


I put the same. Did you have to specify it was a sextet though or is multiplet enough?
Original post by FluffyCommie
Pretty sure the only acceptable form would be:

Aldehyde + 2[o] --> alcohol


*2[H]
Original post by President J
It was all under 2 I thought. As it was a 3 Carbons. Doublet, Doublet, Multiplet


his/her answer was right i think, cus the middle C was attracted to N fom NH2 and the first one attract to O in OH no?/
Original post by ali_t9001
*2[H]


well, thank god I didn't make that mistake in the exam :P
Original post by Ilkonebi
I put the same. Did you have to specify it was a sextet though or is multiplet enough?


It was enough, you can use multiplet for 5 and higher.
Original post by FluffyCommie
Pretty sure the only acceptable form would be:

Aldehyde + 2[o] --> alcohol


I did the same thing by putting an oh don't know if I will loose a mark and doesn't reduction involve 2H instead of 2O

Quick Reply

Latest

Trending

Trending