Simplifying and laws of indices Watch

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HearTheThunder
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#1
Report Thread starter 13 years ago
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Ok I'm doing Intermediate Maths (AQA B) and I know that in the law of indices to simplify x^5 / x^3 you take away.. but on this question I am doing it says:

5) c) Simplify: x^3 / x^3

If you were to take away - does that mean you should simplify this to 0 ??

Also how do you simplify: 2a * 3b * 4c, it already looks simplified to me...
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Featherflare
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Report 13 years ago
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it gives x^3-3 = x^0 = 1
but its pretty obvious anyway (top and bottom are the same)

if you meant 2a x 3b x 4c dats = 24abc
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idiopathic
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(Original post by hearthethunder)
Ok I'm doing Intermediate Maths (AQA B) and I know that in the law of indices to simplify x^5 / x^3 you take away.. but on this question I am doing it says:

5) c) Simplify: x^3 / x^3


If you were to take away - does that mean you should simplify this to 0 ??
You're on the right lines- it would be x^0, which is 1. (anything to the power of 0 is 1). But just think about what happens when you divide something by itself. eg: 2/2 = 1
Also how do you simplify: 2a * 3b * 4c, it already looks simplified to me...
2a * 3b * 4c = 2*3*4*abc = 24abc
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HearTheThunder
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#4
Report Thread starter 13 years ago
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ohh yeah ok i get it now thanks
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