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# does any one know the answers to jan 2003 pure 3 ocr paper watch

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1. hey, iv dun q8 2 b specific, bt i dont no if iv got correct answer so if u hav them if u cud let me no i wud b very grateful, or work it out and i can see if i hav same answer i wud b grateful!!

i) given that u=sin^-1 x

a) value of u when x=1,

u = sin^-1
= pi/2

b) express s in terms of u, and heance write down dx/du in terms of u,

sin U = x, so dx/du = cos U

ii) sow that the substituion u=sin^-1 x transforms the integral
I = INT (between 1 and 0) sin^-1x dx

to

INT (between 0.5pi and 0) u cos u du and hence evaluate I.

is the answer I = 0.5pi -1

thank u!!
2. I get the same answers.
3. YES!!!! wahoo!! thanx!got a Q rite by myself for once!!

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Updated: June 3, 2005
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