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does any one know the answers to jan 2003 pure 3 ocr paper watch

    • Thread Starter

    hey, iv dun q8 2 b specific, bt i dont no if iv got correct answer so if u hav them if u cud let me no i wud b very grateful, or work it out and i can see if i hav same answer i wud b grateful!!

    i) given that u=sin^-1 x

    a) value of u when x=1,

    u = sin^-1
    = pi/2

    b) express s in terms of u, and heance write down dx/du in terms of u,

    sin U = x, so dx/du = cos U

    ii) sow that the substituion u=sin^-1 x transforms the integral
    I = INT (between 1 and 0) sin^-1x dx


    INT (between 0.5pi and 0) u cos u du and hence evaluate I.

    is the answer I = 0.5pi -1

    thank u!!

    I get the same answers.
    • Thread Starter

    YES!!!! wahoo!! thanx!got a Q rite by myself for once!!
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Updated: June 3, 2005

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