Nooo... Intermediate Maths Questions Watch

This discussion is closed.
HearTheThunder
Badges: 14
Rep:
?
#1
Report Thread starter 13 years ago
#1
Yeah OK having trouble scraping a B here, maths being my weakest subject.. but anyway I have two questions here where I got a grand total of 0 marks on both. Can someone help me - HOW do you do these questions?! :

Question 1
Question 2
0
C4>O7
Badges: 5
Rep:
?
#2
Report 13 years ago
#2
For what value of x does the line cross the y-axis?
For what value of y does the line cross the x-axis?
Gradient = change in y/change in x- use the coordinates calculated in a)
0
Chewwy
Badges: 15
Rep:
?
#3
Report 13 years ago
#3
1)

rearrange to nice form:

2y - x = 4
2y = x + 4
y = 0.5x + 2

so, y = 0 when x = -4
x = 0 when y = 2

(by plugging the numbers in)

gradient, uh, well, by converting the equation into the above format we know the grad is a half. or, you can take the two points you know, (-4,0) and (0,2), and then find change in y over change in x.
0
Chewwy
Badges: 15
Rep:
?
#4
Report 13 years ago
#4
2)

angles in same segment... so it's 40 degrees.

opp. angles in cyclic quad... so it's 180 - 40 = 140 degrees.

since it's a tangent, BAD & BCD are right angles. ABCD is a quadrilateral -> internal angles = 360. 360 - 90 - 90 - 2(40) = 100
0
Madprof
Badges: 2
Rep:
?
#5
Report 13 years ago
#5
Question 2
a) i) Angles in a segment rule. Look at the angle already drawn in. You don't have to do any calculations as it says 'write down...'

ii) Look at the quadrilateral with angles x and y in. There is a rule for quadrilaterals in a circle. As this is a one mark question, you don't have to do very much working out at all, just thinking.

b) What's angle ABD? Look at the angle you already know, and the fact that line AD is a tangent. Now you should know what CBD is. Add them together...
0
Madprof
Badges: 2
Rep:
?
#6
Report 13 years ago
#6
Chewwy got there first! Sorry :rolleyes:
0
Expression
Badges: 14
Rep:
?
#7
Report 13 years ago
#7
(Original post by hearthethunder)
Yeah OK having trouble scraping a B here, maths being my weakest subject.. but anyway I have two questions here where I got a grand total of 0 marks on both. Can someone help me - HOW do you do these questions?! :

Question 1
Question 2

Just for the sake of reiteration of what everyone else has said:

Question 1

2y - x = 4

Point A is on the x-axis, ie at a point where y=0.
Substitute y=0.
2(0) - x = 4,
-x = 4,
x=-4.
A(-4,0).

Similarly, Point B is on the y-axis, ie at a point where x=0.
Substitute x=0.
2y - (0) = 4
2y = 4
y = 2
So B(0, 2).


In a linear equation, that is, one in the form of y=mx + c, the gradient is m, and can be read off.

So we desire the given equation of the line, in this form - a simple rearrangement.

Given 2y - x = 4
2y = x + 4
y = 1/2(x + 4)
y = 0.5x + 2

So, the gradient m = 0.5.
0
X
new posts
Latest
My Feed

See more of what you like on
The Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

Personalise

University open days

  • University of East Anglia
    UEA Mini Open Day Undergraduate
    Fri, 4 Jan '19
  • University of Lincoln
    Mini Open Day at the Brayford Campus Undergraduate
    Mon, 7 Jan '19
  • Bournemouth University
    Undergraduate Mini Open Day Undergraduate
    Wed, 9 Jan '19

Did you get less than your required grades and still get into university?

Yes (60)
30.3%
No - I got the required grades (115)
58.08%
No - I missed the required grades and didn't get in (23)
11.62%

Watched Threads

View All