You are Here: Home >< Maths

# Another Angle Question.. Rhombus watch

Announcements
1. Do the same rules apply here as angles in a circle? I don't know.. how do you do this question:
Attached Images

2. (Original post by hearthethunder)
Do the same rules apply here as angles in a circle? I don't know.. how do you do this question:
From definitions of rhombus and Kite, get that system is symmetrical about BE. Draw BE

AED=25

ABD = 55 so BDA = 55 so ADE = 125

SO DAE = X = 180-(125+25) =30

Check with DAB = 180-(55+55) = 180-(55+25+30)

Aitch
3. (Original post by Aitch)
From definitions of rhombus and Kite, get that system is symmetrical about BE. Draw BE

ABD = 55 so BDA = 55 so ADE = 125

SO DAE = X = 30

Check with DAB = 180-(55+55) = 180-(55+25+30)

Aitch
Definitions:

http://mathworld.wolfram.com/Rhombus.html

http://mathworld.wolfram.com/Kite.html

Aitch
4. (Original post by Aitch)
From definitions of rhombus and Kite, get that system is symmetrical about BE. Draw BE

AED=25

ABD = 55 so BDA = 55 so ADE = 125

SO DAE = X = 180-(125+25) =30

Check with DAB = 180-(55+55) = 180-(55+25+30)

Aitch
Where on earth have you got 55 and 25 from.. I only see 110 and 50
5. (Original post by hearthethunder)
Where on earth have you got 55 and 25 from.. I only see 110 and 50
Draw the vertical BE. It bisects these two angles.

Aitch
6. Logical, X = 30,
think about all angles in rhombus must equal 360. (sames true for kite)

7. (Original post by Aitch)
Draw the vertical BE. It bisects these two angles.

Aitch
Ohh yeah so it does
8. (Original post by Vijay1)
Logical, X = 30,
think about all angles in rhombus must equal 360. (sames true for kite)

I don't get how you can apply that rule to this question..
9. (Original post by hearthethunder)
Where on earth have you got 55 and 25 from.. I only see 110 and 50

His first instruction was to construct the line BE, this splits the angle ABC = 110 into ABD = 55 = BCD. and AED = 25 = DEC.
10. ok... from where did you get 125?
11. (Original post by Neo1)
ok... from where did you get 125?

BDE is a straight line. Subtract 55 from it, get 125.

Aitch
12. Huh subtract 55 from where ? lol i dont get it...
13. (Original post by Neo1)
Huh subtract 55 from where ? lol i dont get it...
BDE is 180°

BDA is 55°

Therefore ADE is (180-55)° = 125°

Aitch

TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Updated: June 6, 2005
Today on TSR

### Should I drop out of uni

...to become a pro gamer?

### University open days

• University of Buckingham
Fri, 14 Dec '18
• University of Lincoln
Mini Open Day at the Brayford Campus Undergraduate
Wed, 19 Dec '18
• University of East Anglia
Fri, 4 Jan '19
Poll
Useful resources

### Maths Forum posting guidelines

Not sure where to post? Read the updated guidelines here

### How to use LaTex

Writing equations the easy way

### Study habits of A* students

Top tips from students who have already aced their exams