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Another Angle Question.. Rhombus watch

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    Do the same rules apply here as angles in a circle? I don't know.. how do you do this question:
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    (Original post by hearthethunder)
    Do the same rules apply here as angles in a circle? I don't know.. how do you do this question:
    From definitions of rhombus and Kite, get that system is symmetrical about BE. Draw BE

    AED=25

    ABD = 55 so BDA = 55 so ADE = 125

    SO DAE = X = 180-(125+25) =30

    Check with DAB = 180-(55+55) = 180-(55+25+30)

    Aitch
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    (Original post by Aitch)
    From definitions of rhombus and Kite, get that system is symmetrical about BE. Draw BE

    ABD = 55 so BDA = 55 so ADE = 125

    SO DAE = X = 30

    Check with DAB = 180-(55+55) = 180-(55+25+30)

    Aitch
    Definitions:

    http://mathworld.wolfram.com/Rhombus.html

    http://mathworld.wolfram.com/Kite.html

    Aitch
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    (Original post by Aitch)
    From definitions of rhombus and Kite, get that system is symmetrical about BE. Draw BE

    AED=25

    ABD = 55 so BDA = 55 so ADE = 125

    SO DAE = X = 180-(125+25) =30

    Check with DAB = 180-(55+55) = 180-(55+25+30)

    Aitch
    Where on earth have you got 55 and 25 from.. I only see 110 and 50
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    (Original post by hearthethunder)
    Where on earth have you got 55 and 25 from.. I only see 110 and 50
    Draw the vertical BE. It bisects these two angles.

    Aitch
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    Logical, X = 30,
    think about all angles in rhombus must equal 360. (sames true for kite)

    :rolleyes:
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    (Original post by Aitch)
    Draw the vertical BE. It bisects these two angles.

    Aitch
    Ohh yeah so it does
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    (Original post by Vijay1)
    Logical, X = 30,
    think about all angles in rhombus must equal 360. (sames true for kite)

    :rolleyes:
    I don't get how you can apply that rule to this question..
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    (Original post by hearthethunder)
    Where on earth have you got 55 and 25 from.. I only see 110 and 50

    His first instruction was to construct the line BE, this splits the angle ABC = 110 into ABD = 55 = BCD. and AED = 25 = DEC.
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    ok... from where did you get 125?
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    (Original post by Neo1)
    ok... from where did you get 125?

    BDE is a straight line. Subtract 55 from it, get 125.

    Aitch
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    Huh subtract 55 from where ? lol i dont get it...
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    (Original post by Neo1)
    Huh subtract 55 from where ? lol i dont get it...
    BDE is 180°

    BDA is 55°

    Therefore ADE is (180-55)° = 125°

    Aitch
 
 
 
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