The Student Room Group
Reply 1
HBr (made in situ by heating conc. sulphuric acid and NaBr) will give you a Bromoalkane.

Red phorsphorus iodide will give you the iodoalkane

PCl5 will give you the chlroalkane
Reply 2
kpg
HBr (made in situ by heating conc. sulphuric acid and NaBr) will give you a Bromoalkane.

Red phorsphorus iodide will give you the iodoalkane

PCl5 will give you the chlroalkane


thanks. are the last two room temp?
Reply 3
cjoc28
i know the nucleophilic substitution reaction between a halogenoalkane and aqueous KOH gives an alcohol... but i always forget, how to you go backwards?

for example, what are the reagents/conditions for the conversion of butan-1-ol to 1-bromobutane??

thanks

HBr(aq)
NaBr(s) and conc. H2SO4
Heat under reflux
Reply 4
depends what you are making.

react PCl5 with an alcohol to make chloroalkane

C2H5OH + PCl5 ---> C2H5Cl + HCl + POCl3
conditions: at room temp. and alcohol must be dry


react solid sodium bromind and conc. sulphuric acid to give bromoalkane

NaBr + H2SO4 --> HBr + NaHSO4
then HBr + C2H5OH --> C2H5Br + H2O
conditions: add H2SO4 mixed with alcohol to solid NaBr @ room temp


react phosphorus and iodine to give iodoalkane:

2P + 3I2 --> 2PI3
then 3C2H5OH + PI3 --> 3C2H5I + H3PO3
conditions: add the alcolod to a mixture of moist red phosphorus and iodine @ room temp
Reply 5
thanks!!
Reply 6
sulphuric acid heat under eflux. HBr