Sorry have been trying to figure this out for aages but rely need help.
Distance between two wave crests is 0.24m and the frequency of the wave is 3.6 hz. Calculate wave speed. (can do this bit)
V = f x wavelength
v = 3.6 x 0.48
v = 1.728
The frequency is doubled to 7.2 hz. Determine changes, if any, to
1. wave speed
I dont understand how can do this because if frequency doubles then surely one of these must remain constant for the other to change proportionally to the frequency.But then how can we say which remains constant??
Soz this is probs trés easy, but i am totally confused!
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Aah physics wave question watch
- Thread Starter
- 09-06-2005 18:46
- 09-06-2005 18:57
Why do you double the distance between the wave crests?
The Distance between to wave crests is the wavelength.
Wavelength doesnt change.
Wave Speed Increases, because frequency increases
- 09-06-2005 20:22
I actully I kinda disagree,I think wavelength will half and speed will stay the same
- 09-06-2005 21:06
I agree with habosh.
- 09-06-2005 21:13
1/wavelength proportional to freq
speed will remain the same
double freq, and half the wavelength