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abey_27
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#1
heyy,
calcium reacts with oxygen to form calcium oxide. What mass of oxygen will react exactly with 60g of calcium?
I know the relative atomic mass of calcium is 40, and oxygen is 16, but how exactly do i use this information to find out what mass of oxygen will react exactly with 60g of calcium?
thanks for your help!
calcium reacts with oxygen to form calcium oxide. What mass of oxygen will react exactly with 60g of calcium?
I know the relative atomic mass of calcium is 40, and oxygen is 16, but how exactly do i use this information to find out what mass of oxygen will react exactly with 60g of calcium?
thanks for your help!
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rainbowbex
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#2
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#2
(Original post by abey_27)
heyy,
calcium reacts with oxygen to form calcium oxide. What mass of oxygen will react exactly with 60g of calcium?
I know the relative atomic mass of calcium is 40, and oxygen is 16, but how exactly do i use this information to find out what mass of oxygen will react exactly with 60g of calcium?
thanks for your help!
heyy,
calcium reacts with oxygen to form calcium oxide. What mass of oxygen will react exactly with 60g of calcium?
I know the relative atomic mass of calcium is 40, and oxygen is 16, but how exactly do i use this information to find out what mass of oxygen will react exactly with 60g of calcium?
thanks for your help!
find the moles of calcium in 60g (moles = mass/Mr)
use the equation to find moles of O2 needed (in this reaction the ratio is 1:2 so divide moles of Ca by 2)
use moles of O2 to calculate mass (mass = moles x Mr)
EDIT: ask me to explain anything that didn't make sense
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wer343lit
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#3
2Ca + 02 >>>>>> 2Cao
Moles = Mass/Mr
Moles of Calcium = 60/40 = 1.5
Ratio = 2:1
Moles of O2 = 0.75
Mass = Mr x Moles = 0.75 x 32 = 24g
Moles = Mass/Mr
Moles of Calcium = 60/40 = 1.5
Ratio = 2:1
Moles of O2 = 0.75
Mass = Mr x Moles = 0.75 x 32 = 24g
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Zedd
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#4
1.0M of CaO = 40g + 16g = 56g
40 / 16 = 2.5
60 / 2.5 = 24
That is how I would figure it out, so you would theoretically need 24g of oxygen to react with 60g of calcium.
EDIT- LOL, I think we'll have confused her with our different methods...
40 / 16 = 2.5
60 / 2.5 = 24
That is how I would figure it out, so you would theoretically need 24g of oxygen to react with 60g of calcium.
EDIT- LOL, I think we'll have confused her with our different methods...
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rainbowbex
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#5
(Original post by Zedd)
1.0M of CaO = 40g + 16g = 56g
40 / 16 = 2.5
60 / 2.5 = 24
That is how I would figure it out, so you would theoretically need 24g of oxygen to react with 60g of calcium.
EDIT- LOL, I think we'll have confused her with our different methods...
1.0M of CaO = 40g + 16g = 56g
40 / 16 = 2.5
60 / 2.5 = 24
That is how I would figure it out, so you would theoretically need 24g of oxygen to react with 60g of calcium.
EDIT- LOL, I think we'll have confused her with our different methods...
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Nren
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#6
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#6
o2+2Ca=2cao
the number of moles =given mass in grams divided by the relative mass
u knw that it is o2 +2ca rit so basicall they react wid the ratio 1:1
first u find out how many moles r there in 60 grrams of ca
n=60 divided by 40 =1.5 moles
as i said b4 they react wid 1:1 ratio so
1.5 moles of oxygen will react with 1.5 moles of ca
1.5=x divided by 16=10.6666666667
so 10.6 gms of oxygen is required
hey im sure this is rit so add me to ur frnds list
the number of moles =given mass in grams divided by the relative mass
u knw that it is o2 +2ca rit so basicall they react wid the ratio 1:1
first u find out how many moles r there in 60 grrams of ca
n=60 divided by 40 =1.5 moles
as i said b4 they react wid 1:1 ratio so
1.5 moles of oxygen will react with 1.5 moles of ca
1.5=x divided by 16=10.6666666667
so 10.6 gms of oxygen is required
hey im sure this is rit so add me to ur frnds list
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wer343lit
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#7
(Original post by rainbowbex)
Mine and jontys the same.. I just thought best to leave her to actually work it out herself.. yours tho mate.... I don't understannnd!!
Mine and jontys the same.. I just thought best to leave her to actually work it out herself.. yours tho mate.... I don't understannnd!!
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wer343lit
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#8
(Original post by Nren)
o2+2Ca=2cao
the number of moles =given mass in grams divided by the relative mass
u knw that it is o2 +2ca rit so basicall they react wid the ratio 1:1
first u find out how many moles r there in 60 grrams of ca
n=60 divided by 40 =1.5 moles
as i said b4 they react wid 1:1 ratio so
1.5 moles of oxygen will react with 1.5 moles of ca
1.5=x divided by 16=10.6666666667
so 10.6 gms of oxygen is required
hey im sure this is rit so add me to ur frnds list
o2+2Ca=2cao
the number of moles =given mass in grams divided by the relative mass
u knw that it is o2 +2ca rit so basicall they react wid the ratio 1:1
first u find out how many moles r there in 60 grrams of ca
n=60 divided by 40 =1.5 moles
as i said b4 they react wid 1:1 ratio so
1.5 moles of oxygen will react with 1.5 moles of ca
1.5=x divided by 16=10.6666666667
so 10.6 gms of oxygen is required
hey im sure this is rit so add me to ur frnds list
2 Ca : O2
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Zedd
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#9
(Original post by Jonty99)
I think he worked out the mass of product, so then the mass of reactants must add to give that. Never seen that method before though.
I think he worked out the mass of product, so then the mass of reactants must add to give that. Never seen that method before though.
It might be that I've developed a backwards method from my work, I do analysis so I tend to have to work back and find out why something is wrong.
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maisiemets
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#10
(Original post by rainbowbex)
write an equation for the reaction, O2 + 2Ca ----> 2CaO (I think)
find the moles of calcium in 60g (moles = mass/Mr)
use the equation to find moles of O2 needed (in this reaction the ratio is 1:2 so divide moles of Ca by 2)
use moles of O2 to calculate mass (mass = moles x Mr)
EDIT: ask me to explain anything that didn't make sense
write an equation for the reaction, O2 + 2Ca ----> 2CaO (I think)
find the moles of calcium in 60g (moles = mass/Mr)
use the equation to find moles of O2 needed (in this reaction the ratio is 1:2 so divide moles of Ca by 2)
use moles of O2 to calculate mass (mass = moles x Mr)
EDIT: ask me to explain anything that didn't make sense
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username2889812
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username2889812
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#12
(Original post by maisiemets)
with the last step of working out the mass, do i use the relative atomic mass of just calcium of calcium and oxygen added together
with the last step of working out the mass, do i use the relative atomic mass of just calcium of calcium and oxygen added together
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