Is this correct? :( Watch

anonymous14
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#1
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Hello,

I have attached the question. The answer I get is

2, root 2(numerator)
64 (denominator)

Please can someone check this work.
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Small123
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#2
(Original post by anonymous14)
Hello,

I have attached the question. The answer I get is

2, root 2(numerator)
64 (denominator)

Please can someone check this work.
You can simplify further.
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coldfusion
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(Original post by Small123)
You can simplify further.
Not by much though :p:
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anonymous14
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(Original post by Small123)
You can simplify further.
I'm sorry, but I can't see, how
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Small123
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(Original post by coldfusion)
Not by much though :p:
I cant be too specific can I :rolleyes: . But yes the simplification is very minor :p:
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bigmo7
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(Original post by anonymous14)
I'm sorry, but I can't see, how
Divide throughout by a number?
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Small123
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(Original post by anonymous14)
I'm sorry, but I can't see, how
\displaystyle\frac{2\sqrt2}{64}
Both numbers are even
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member169510
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(Original post by anonymous14)
I'm sorry, but I can't see, how
what can you divide the bottom and top by?
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andy5788
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In worrying so much about the surds you've missed something very obvious... Don't worry, we all do it!
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anonymous14
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(Original post by JumpingJonny)
what can you divide the bottom and top by?
Well, you could divide it by 2, then the answer is:

2 root (numerator)
32 (denominator)

?
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member169510
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(Original post by anonymous14)
Well, you could divide it by 2, then the answer is:

2 root (numerator)
32 (denominator)

?
Correct :yep:
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anonymous14
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(Original post by andy5788)
In worrying so much about the surds you've missed something very obvious... Don't worry, we all do it!
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anonymous14
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(Original post by JumpingJonny)
Correct :yep:
Thank you everyone.
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