# easy physics problem....need help!!!Watch

Thread starter 9 years ago
#1
A sports car is advertised to be able to stop in a distance of 50m from a speed of 90k/h. What is its aceleration in m/s^2? How many g's is this?
0
9 years ago
#2
(Original post by dsolmon)
A sports car is advertised to be able to stop in a distance of 50m from a speed of 90k/h. What is its aceleration in m/s^2? How many g's is this?

Acc = (v-u)/t

v = 0
u = 90 km/h (convert in m's)
t = can be worked out

then just sub in the equation!
0
9 years ago
#3
You would have to use suvat in order to work this out,
S=50m
U= (90,000/3600)
V=0
A=?
T=?

So using the formula V^2 = U^2 +2AS ...you can work out A (acceleration) , if you divide this by 9.81..it will tell you how many g's it is.
0
Thread starter 9 years ago
#4
Thank you so much! I want to be able to do this on my own but i have a hard time trying to figure out where to put the different numbers in the formulas.
So the answer is 6.25m/s^2, 0.64g's, right?
0
9 years ago
#5
(Original post by dsolmon)
Thank you so much! I want to be able to do this on my own but i have a hard time trying to figure out where to put the different numbers in the formulas.
So the answer is 6.25m/s^2, 0.64g's, right?
Yep that is correct
0
Thread starter 9 years ago
#6
(Original post by sk88)
Yep that is correct
Sweet! hey, maybe you could help me with my other thread i posted. Its is titled: Having a hard time getting it right!!
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