The Student Room Group
Reply 1
What was your answer for i) then?
Reply 2
For part ii) I used two equations.

F = -GMm/r^2 and F = mv^2/r

Equate them, cancel the m's and then solve to get an answer of about 5.8 x 10^-23 as long as your speed is ok.
Reply 3
[br]F=GMmr2[br]F = \frac {-GMm}{r^2}

And

[br]F=mv2r[br]F = \frac {mv^2}{r}

Equate
GMmr2=mv2r\frac {-GMm}{r^2} = \frac {mv^2}{r}

Divide each side by m
GMr2=v2r\frac {-GM}{r^2} = \frac {v^2}{r}

Cancel an r on each side
GMr=v2\frac {-GM}{r} = {v^2}

Multiply the final r onto the RHS, and divide each side by G. Leaving M which is the mass of Mars
M=rv2G M = \frac{rv^2}{G}
Thanks, I got the same answer by following your steps so my speed should be correct :p:

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