This discussion is now closed.
Check out other Related discussions
- A level maths UMS marks!!!
- BMAT practise papers advice
- Can You Writing Under The Lines in GCSE??
- What units do I need for Edexcel IAL or IAS Further Maths
- Is it over?
- OCR a level chemistry summary questions answers
- Ocr chemistry a exam-style questions
- how did peoples ENGAA go?
- physics question
- OCR A Level Mathematics B (MEI) Paper 2 (H640/02) - 11th June 2024 [Exam Chat]
- A level Past papers
- Projectiles A2 Mechanics (please help)
- Alevel maths resit
- PG online computer science test answers
- A levels
- Ocr alevel chem
- how can I actually get an A/A* in ocr a chemistry?
- what website gives the content that's most accurate for OCR biology?
- Can I get an A/A* just by using the CGP book and exam board book for A level bio OCR
- science a levels
Scroll to see replies
Well these are the answers anyway....
Statistics 2 – June 2001 – Answers
1 5.
2 (i) Distribution of R is B(60, 0.05); since n > 50 and np < 5, a Poisson
approximation (R ~ Po(3)) would be appropriate.
(ii) Assign a number to each pupil in the school and use random number tables to
choose the sample of size 60.
3 0.887.
4 (i) ;
(ii) r  5; if r = 4, accept the null hypothesis – there is no evidence that
employee is late on more than 1 day in 10;
(iii) 0.630.
5 (i) Only a breaking strength less than that claimed is a cause for concern;
(ii) Reject null hypothesis (acceptance region is > 12953) – the company’s
claim that the breaking strength is 13000 N is not justified.
(iii) Central Limit Theorem needed because breaking strengths are not given to
be normally distributed.
6 (i) 3;
(ii) 0.125;
(iii) 2.75;
(iv) 2.79.
7 (i) The typing errors occur independently of each other;
(ii) 0.554;
(iii) 0.184;
(iv) 0.0923;
(v) 1.05 minutes.
Statistics 2 – June 2001 – Answers
1 5.
2 (i) Distribution of R is B(60, 0.05); since n > 50 and np < 5, a Poisson
approximation (R ~ Po(3)) would be appropriate.
(ii) Assign a number to each pupil in the school and use random number tables to
choose the sample of size 60.
3 0.887.
4 (i) ;
(ii) r  5; if r = 4, accept the null hypothesis – there is no evidence that
employee is late on more than 1 day in 10;
(iii) 0.630.
5 (i) Only a breaking strength less than that claimed is a cause for concern;
(ii) Reject null hypothesis (acceptance region is > 12953) – the company’s
claim that the breaking strength is 13000 N is not justified.
(iii) Central Limit Theorem needed because breaking strengths are not given to
be normally distributed.
6 (i) 3;
(ii) 0.125;
(iii) 2.75;
(iv) 2.79.
7 (i) The typing errors occur independently of each other;
(ii) 0.554;
(iii) 0.184;
(iv) 0.0923;
(v) 1.05 minutes.
Saiyan
Hey.... can anyone tell me how to do Question 4 on that paper (Jan 2001)?
The hypothesis question... I don't know what the question is asking for... Binomial hypothesis? Normal? Poission?
Thanks.
The hypothesis question... I don't know what the question is asking for... Binomial hypothesis? Normal? Poission?
Thanks.
i didnt get the answers correct for question 4 calculations.
but i reckon it will be poisson distribution for the hyposthesis, because he says he's late no more than 1 in 10 days, λ=1, therefore in 20 days, λ=2!
so for the hypothesis
H0 : λ=2
H1 : λ>2
is that what your'e asking?
Tazzie
i didnt get the answers correct for question 4 calculations.
but i reckon it will be poisson distribution for the hyposthesis, because he says he's late no more than 1 in 10 days, λ=1, therefore in 20 days, λ=2!
so for the hypothesis
H0 : λ=2
H1 : λ>2
is that what your'e asking?
but i reckon it will be poisson distribution for the hyposthesis, because he says he's late no more than 1 in 10 days, λ=1, therefore in 20 days, λ=2!
so for the hypothesis
H0 : λ=2
H1 : λ>2
is that what your'e asking?
haha... I've done it now..
it was
Ho: Mu = 1/10
H1: Mu > 1/10
los 5%
onetail test
Under Ho
X~B(20,1/10)
P(X<=3) = 0.8670
<---- 0.9
P(X<=4) = 0.9568
therefore,
P(X>3) = 0.133
<----0.1
P(X>4) = 0.0432
Decision,
Reject Ho if X>4 (X=>5)
r days = 4
not in rejection zone so... no evidence
etc etc
(i think it was that binomial proportion thingy topic)hmmm... that poisson way looks kind of dodgy? lol. Don't think it would work like that. I think you've thought of lamba value wrong.
Bye....
Tazzie
see i thought it was that too! i wrtoe it up, and then deleted the post!
imconfused!
can u guys please clarify why its one and the not the other!
imconfused!
can u guys please clarify why its one and the not the other!
hehe...I have the same problem... but in this case they didn't give us one average CONSTANT value for being away (poisson)... and ho and h1 were in fractions... so I guessed it would be binomial.... proportion testing..
Saiyan
hehe...I have the same problem... but in this case they didn't give us one average CONSTANT value for being away (poisson)... and ho and h1 were in fractions... so I guessed it would be binomial.... proportion testing..
and this binomial proportioney thing. i can work it in s3, but dont remember doing it in s2. would you just look up the tables to do it?
Tazzie
and this binomial proportioney thing. i can work it in s3, but dont remember doing it in s2. would you just look up the tables to do it?
oh wait sorry... I just realized that was just a normal binomial hypothesis question!!..
Hypothesis test of proportion is different.. here is an example question of it.
ho: p=1/4
h1: p>1/4
one tail test
los 5%
Carried out 100 times leading to 32 successes
under ho
X~B(100,0.25)
using normal approx
X~N(25,18.75)
to find C so that P(X>C-½) remember? you have to minus ½... can't remember why but i just know you have to
standardising
P(Z> (c-½-25)/√18.75) = 0.05
P(Z>1.645) = 0.05
Hence
(C-½-25)/(√18.75) = 1.645
therefore c = 32.6
decision
X>=33 Reject Ho
X<33 Accept Ho
Observed value x = 32
32<33 therefore accept Ho
No evidence that p is less than 1/4
nope, havent done the june 04 yet.
but i have a question anyway.
I have X, distributed by poisson, with mean 20.
PART 1: use the exact distribution to find P(X=22)
That's fine, just from the tables.
PART 2: use a suitable appoorximation to find P(X=22)
I need help with the seond part. Iaproximate it the normal, so thats
X-N(20,20)....But then?
but i have a question anyway.
I have X, distributed by poisson, with mean 20.
PART 1: use the exact distribution to find P(X=22)
That's fine, just from the tables.
PART 2: use a suitable appoorximation to find P(X=22)
I need help with the seond part. Iaproximate it the normal, so thats
X-N(20,20)....But then?
Related discussions
- A level maths UMS marks!!!
- BMAT practise papers advice
- Can You Writing Under The Lines in GCSE??
- What units do I need for Edexcel IAL or IAS Further Maths
- Is it over?
- OCR a level chemistry summary questions answers
- Ocr chemistry a exam-style questions
- how did peoples ENGAA go?
- physics question
- OCR A Level Mathematics B (MEI) Paper 2 (H640/02) - 11th June 2024 [Exam Chat]
- A level Past papers
- Projectiles A2 Mechanics (please help)
- Alevel maths resit
- PG online computer science test answers
- A levels
- Ocr alevel chem
- how can I actually get an A/A* in ocr a chemistry?
- what website gives the content that's most accurate for OCR biology?
- Can I get an A/A* just by using the CGP book and exam board book for A level bio OCR
- science a levels
Latest
Trending
Last reply 4 days ago
can someone please explain what principle domain is and why the answer is a not c?Maths
0
13
