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Mechanics Help!
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2776
lol
I have found that after moving 2 m, the velocity is root 2g.
I have found that after moving 2 m, the velocity is root 2g.
That's correct.
king of swords
That's correct.
king of swords
s = ?, u = ?, a = g, t = 0.2
so s = tu + ½at^2.....then h = s + 2.
so s = tu + ½at^2.....then h = s + 2.
therefore here: u = root(2g)
king of swords
When A moves 2m B also moves 2m. From then on B accelerates only due to gravity since there is no tension left in the string.
So:
s = ?, u = ?, a = g, t = 0.2
so s = tu + ½at^2.....then h = s + 2.
So:
s = ?, u = ?, a = g, t = 0.2
so s = tu + ½at^2.....then h = s + 2.
i used:
v=u +at
v= (root 2g) + (9.8x0.2)
v=6.39
s= 0.5 (u+v)t
s=0.5(root2g+6.39)0.2
s=1.08
since s=h-2
therefore
1.08+2= 3.08m
2776
i used:
v=u +at
v= (root 2g) + (9.8x0.2)
v=6.39
s= 0.5 (u+v)t
s=0.5(root2g+6.39)0.2
s=1.08
since s=h-2
therefore
1.08+2= 3.08m
v=u +at
v= (root 2g) + (9.8x0.2)
v=6.39
s= 0.5 (u+v)t
s=0.5(root2g+6.39)0.2
s=1.08
since s=h-2
therefore
1.08+2= 3.08m
that's fine
ok
there'sanother question im a bit stuck on :s
if any one has soem free time a lil help would be appreciated
A particle is at equilibrium under the action of focres 4N due north , 8N west and 5 root 2 N south east and P. Find the magnitude and direction of P.
I think i need to resolve vertically and horizontally, equate to zero and form a simultaneous equation.
there'sanother question im a bit stuck on :s
if any one has soem free time a lil help would be appreciated
A particle is at equilibrium under the action of focres 4N due north , 8N west and 5 root 2 N south east and P. Find the magnitude and direction of P.
I think i need to resolve vertically and horizontally, equate to zero and form a simultaneous equation.
MIZZ
i get 9 + Psin θ
-3 + Pcos θ
now i have to make that simultaneous???
-3 + Pcos θ
now i have to make that simultaneous???
yes, but have proper equations first, ie. 9 + Psin θ = 0 and -3 + Pcos θ = 0.
MIZZ
ive equated them
but as there are 2 unknowns :s
but as there are 2 unknowns :s
oh yeah!
85ah11
Put the 9 and -3 over to the other side and divide the sin equation by the cos (ie tan 8 = -3). Find 8 and then substitute into one equation to find P.
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