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Reply 1

molar ratio of aluminium oxide to aluminium is 1:2,

mol of aluminium for 1kg = mass/molar mass = 1000g/27 g mol^-1 = 37.04 mol

therefore mol of aluminium oxide = 0.5 x 37.04 = 18.52 mol

hence mass = mol x molar mass of aluminium oxide
= 18.52 x 102 = 1889.04g = 1.89 kg (3SF)

for the other parts, simply work out what fraction they are of 1kg and multiply appropriately to get those answers. hope that helped!

Reply 2

All in kilograms yea...
From equation ratio of Al to Al2O3 is 4:2 = 2:1 (therefore multiply moles of Al my .5)
a) (1/27) = number of moles of Aluminium
Moles of Al2O3 = 1/54
Mass of Al2O3 = (1/54)*RMM of Al2O3 = (1/54)*102 = 17/9 Kg
If you do the same thing for all the masses then it should be fine.... is that answa right?

Reply 3

mackin boi
All in kilograms yea...
From equation ratio of Al to Al2O3 is 4:2 = 2:1 (therefore multiply moles of Al my .5)
a) (1/27) = number of moles of Aluminium
Moles of Al2O3 = 1/54
Mass of Al2O3 = (1/54)*RMM of Al2O3 = (1/54)*102 = 17/9 Kg
If you do the same thing for all the masses then it should be fine.... is that answa right?


yeah that works, but surely to be correct you must convert from kg to g, because the molar masses are in g mol^-1, even though the factor of 1000 cancels out at the end?

Reply 4

Yep, thanks! You're right :smile:

Reply 5

moojoo
yeah that works, but surely to be correct you must convert from kg to g, because the molar masses are in g mol^-1, even though the factor of 1000 cancels out at the end?


i was always taught to just forget the factor because it takes up time in the xam....and it sort of complicates it ... s'all gud

Reply 6

kool, yeah that's fair enough i suppose it does take time

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