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# Maths question, help needed watch

1. Hey, just did a maths past paper, easy peasy EXCEPT for this bad boy right here.

Find the values of a and b when:

x² - 6x + a = (x + b)²

I've been going round in circles, can't work it out. Can someone post the answer, and how you get there? cheers
2. cant be bothered
need a calc and paper to work it out by hand
but am too tired

3. (Original post by InTeRRoGaToR)
cant be bothered
need a calc and paper to work it out by hand
but am too tired

haha what's that? you dont know how to do it? never mind, unless you wanna prove me wrong
4. haha
dnt make me laff
ur jus tryin to get answer outta me... jus that i really cant be bothered
and dont bother postin anythin back cos i aint gna look
so i win
much love fool
5. Im not an A grade student but won't you have to make it so that x^2 + mx + y = 0 or other. Working on it.
6. someone smarter than "InTeRRoGaToR", sorry, I mean someone with a calculator and more time than "InTeRRoGaToR", can you help me out?
7. (Original post by soulsussed)
Im not an A grade student but won't you have to make it so that x^2 + mx + y = 0 or other. Working on it.
could be?
8. you dont need calculator here obviously. I dont think it is possible to find values for a and b, but you can turn a or b into a subject.
9. (Original post by IZZY!)
you dont need calculator here obviously. I dont think it is possible to find values for a and b, but you can turn a or b into a subject.
yeh no doubt, but it says "find the values of a and b".. unless it's a typo in the exam paper, but thats quite unlikely
10. I've got a = b^2 +6x so far

Tell you how I got there:

x^2 - 6x +a = x^2 + b^2 (-x^2 from both sides)

-6x + a = b^2 (rearrange by adding 6x)

a = b^2 + 6x
11. so is the question 100% similar to what you have written?Does it just show the equation and say find the values of a and b?or are the equation written separately?perhaps you may try to solve them separately
12. It's probaby totally wrong as I don't know where to go now.
13. (Original post by hellohello)
Hey, just did a maths past paper, easy peasy EXCEPT for this bad boy right here.

Find the values of a and b when:

x² - 6x + a = (x + b)²

I've been going round in circles, can't work it out. Can someone post the answer, and how you get there? cheers
a= 9 and b= -3 would work but I don' know a way of proving that.
14. (Original post by soulsussed)
I've got a = b^2 +6x so far

Tell you how I got there:

x^2 - 6x +a = x^2 + b^2 (-x^2 from both sides)

-6x + a = b^2 (rearrange by adding 6x)

a = b^2 + 6x
firslly (x+b)^2 isnt x^2 + b^2
it is x^2 + 2bx+b^2
secondly you didnt find a value for an a, u turned a into a subject
15. (Original post by IZZY!)
so is the question 100% similar to what you have written?Does it just show the equation and say find the values of a and b?or are the equation written separately?perhaps you may try to solve them separately
Yeh, what I wrote in the first post is an exact copy of the question. find the values of a and b, when x²-6x+a=(x+b)²
16. Expanding (x + b)^2 you get, x^2 + 2bx + b^2

Therefore:

2b = -6 and b^2 = a

From there it's an easy solve to get b=-3 and a=9
17. try to do them separately using the formula
I cant type it on comp cuz i cant find all the symbols and i dont want to go to microsoft word.lol.
18. (Original post by hellohello)
Hey, just did a maths past paper, easy peasy EXCEPT for this bad boy right here.

Find the values of a and b when:

x² - 6x + a = (x + b)²

I've been going round in circles, can't work it out. Can someone post the answer, and how you get there? cheers
Ill giv it a go

x²-6x+a=x²+2bx+b²

Then Remove like terms

then: 6x-a=2bx+b²

therefore:5x-a=2b+b²

Sh** i'm stuck-lil help plz
19. (Original post by soulsussed)
Do you not get my solution? Wait... +/- error... ****
Ok.. now it's correct.

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