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# mark schemes for edexcel phy 4 and 5 watch

1. hi does anyone know where i can get full mark schemes for edexcel 4 and 5. or does anyone have them to send them to me?. thanx
2. www.ktaggart.com
some of them are handwritten but they still are the same...
3. (Original post by mackin boi)
www.ktaggart.com
some of them are handwritten but they still are the same...
yep will checked this out. cheers
4. does anyone by any chance have the answers to Phy 5 June 03 qu 5 and 6?
5. 5) Charge Distributed on spheres marked on diagram:
Left hand sphere positive
Right hand sphere negative
Arrow on field line to indictate direction:
Direction on one field, left to right.

Work done:

i) 0 eV
ii) -50eV

6)

i) F = GM(earth)m / R^2
ii) F = GM(moon)m / r^2

Distance R:

GM(earth)m / R^2 = GM(moon)m / r^2

R = 3.5 x 10^7 m

Those sound like the right questions? ( copied from the mark scheme)
6. (Original post by Migraine)
5) Charge Distributed on spheres marked on diagram:
Left hand sphere positive
Right hand sphere negative
Arrow on field line to indictate direction:
Direction on one field, left to right.

Work done:

i) 0 eV
ii) -50eV

6)

i) F = GM(earth)m / R^2
ii) F = GM(moon)m / r^2

Distance R:

GM(earth)m / R^2 = GM(moon)m / r^2

R = 3.5 x 10^7 m

Those sound like the right questions? ( copied from the mark scheme)
cheers mate.

wud u be able to send a copy of the mark scheme to my email address. like all the ones u hve or so?
7. I have all mine in paper form i'm afraid, they're not on my computer :/
8. (Original post by Migraine)
I have all mine in paper form i'm afraid, they're not on my computer :/

ok. np

pls can u look at this question. its pretty easy i should think

(Jan 03) qu 4. A metal "slinky" spring can be used as a long solenoid. It is stretched out so that each turn is 1.6 cm from its nearest neighbour. A current of 0.50 A is passed through the coils of the solenoid.

Calculate the number of turns per metre in the solenoid. (1)

(jan 03) qu1
The capacitors are then joined together in parallel with their positive plates connected together
Hence calculate the total energy stored by the capacitors after connection. (3)
Suggest why there is a loss of stored energy when the capacitors are connected. (2)

9. Q4.
1m has 100cm
100/1.6 = 62.5 or 63 coils in the solenoid.

Q1.
Total charge is : 4*10^-4 C
Total capacitance - worked out from previous sections: 5microF

E=Q^2 / 2C (That eq is found from our NAS book page 29.)

E=(4*10^-4)^2 / 2*5*10^-6

E= 0.016J

10. (Original post by LT0918)
Q4.
1m has 100cm
100/1.6 = 62.5 or 63 coils in the solenoid.

Q1.
Total charge is : 4*10^-4 C
Total capacitance - worked out from previous sections: 5microF

E=Q^2 / 2C (That eq is found from our NAS book page 29.)

E=(4*10^-4)^2 / 2*5*10^-6

E= 0.016J

Dohjeh !!!

i was doing the inverse thats y i was getting a wrong answer. ie 1.6/100

the capacitor one. i wasnt too sure cos the total charge is when the applied PD that it has originally if u get me.
11. Please! pLEASE!! Please!!!, LT0198 explain that first question, I don't have a clue of what u just did?
by d way, tz up! andyj72
12. lt0918, did u assume that d total length of d solenoid was 100cm ?
13. Mike,

I have the paper from Jan03, the question said that the solenoid was 1m long !
14. It doesnt say the solenoid is 1m long! n = turns density ie the number of turns per metre length which in this case is 100/1.6 = 62.5
15. has ne 1 got the mark sheme for jan 05, if not can ne 1 help - i couldnt do this qu

qu 4

Explain,if the wire had twice the diameter, the current would have to be increased by a factor fo four to just lift the wire above the surface of the bench.

( the previous bit shows magnetic fields lines with a wire of lenght 0.4 m of mass 0.5g and the magnetic flux is 2 * 10 ^-2 T.
16. (Original post by Economist)
It doesnt say the solenoid is 1m long! n = turns density ie the number of turns per metre length which in this case is 100/1.6 = 62.5
My mistake, thanks for pointing that out... too much revision gets to you ARG.

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