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1. Hi i am very stuck with this quesion can you please answer it. Much appreciated.

1) An object P of mass 0.2kg hangs by a string from a point O of the roof of a lorry. The lorry is moving horizontallt with constant acceleration of a ms-2. and the string makes a constant angle of 8 dgree with the vertical as shown in the diagram.

can you please show me a method on how to do these tension/string type questions?

thx alot
2. well basically u resolve the forces into horizontal n vertical components, provided the system is in equilibrium
what do u need to find in this question? tell me that so i can show u
generally, for a tension in a string at angle θ with the vertical,
the vertical component= Tcosθ
the horizontal component= Tsinθ
3. draw the particle with its weight acting down.
Draw a string attached to it at angle @ to the vertical (the same angle as the one shown in your lorry pic)
The tension in the string is T, acting away from the particle.
Resolve the tension T into horizontal and vertical components.
The vertical component = the mass (converted to newtons)
The horizontal component in the accelerating force.
Use this component in Newtons 2nd law (F=ma)

You now have two eqns.

square both eqns to get T in terms of m, g and a.

divide one eqn by 'tother to get [email protected] in terms of a and g.

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