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    right i have this question, and i dont know how do answer it, could anybody possibly help?
    It has a circumference of 6km and accelerates protons and antiprotons to 1000 GeV (1 TeV). Calculate the wavelength of the protons produced by this machine. (h = 6.6 x 10-34 Js, c = 3.0 x 108ms-1, e = 1.6 x 10-19 C)

    The answer is 1.2375 x 10^(-18)

    Help would be so much appreciated!
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    What's "it"?
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    Particle accelerator???
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    yep thats the one
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    convert ev's into joules so times by charge
    (1x10^12)*(1.6x10^-19) that gets the energy (1.6x10^-7)J
    energy/h gives frequency of 2.42x10^26hz
    and taking V to be the speed of light and using v=f(lamda) i get to 1.2375x10^-18
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    someone is doing phy4 tomorrow morning

    good luck yeah.
 
 
 
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Updated: June 15, 2005
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