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# Questioning mark schemes..... again! watch

1. Can someone work this out please?
I have an answer - it's not the same as the mark scheme but I can't see where I've gone wrong...

Express as a single fraction in its simplest form:
(x^2 - 8x + 15)/(x^2 - 9) X (2x^2 + 6x)/[(x - 5)^2]

Thanks.
Laura xxx
2. Change x^2 - 8x + 15 to (x-5)(x-3)
Change 2x^2 + 6x to 2x(x+3)
Change x^2 - 9 to (x-3)(x+3)
Now you have 2x(x-5)(x-3)(x+3) / (x+3)(x-3)(x-5)(x-5)
Cancel down, and you get 2x/(x-5)
Is that the answer in the book?
3. yes - thanks

I made a stupid mistake when factorising. (i need some dinner methinks!)

Laura xxxx

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