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    Anybody take this paper today?

    I thought it wasn't too bad and the comprehensive paper was quite self-explanatory.
    How did everyone else find it? I did really badly in my M2 paper so hopefully this P3 paper can still scrape me an A :s:
    Hope everyone did well,
    love rmyl xxx
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    I thought it was pretty hard. Question 3 was really hard and I didn't understand any of the double angle stuff, but the rest of it was alrite. Question 4 was wierd but I think it went quite well.
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    All of the questions were fine, i'll post up my answers just to see if i got them correct
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    yay! its over
    i thought it was ok as far as a levels go
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    Well question one seemed abit too easy at times,
    Question two didnt see too bad, for hte implicite differentiation did people do this method

    y+ ln y = sinx
    dy/dx + 1/y dy/dx = cosx
    dy/dx (1 + 1/y) = cos x
    dy/dx ((y+1)/y) = cos x
    dy/dx = (ycosx)/(y+1)

    Also the integration question

    dy/dx = 5y/(2+x)(1-2x)

    ∫ 1/y dy = ∫ 5/(2+x)(1-2x) dx
    ln y = ∫(1/(2+x) + 2/(1-2x)) dx
    ln y = ln (2+x) - ln(1-2x) + c
    ln y = ln ((2+x)/(1-2x) +c
    y = (2+x)/(1-2x) + ec where ec = k
    y = (2+x)/(1-2x) + k
    when y = 2 x = 0
    2 = 2/1 + k
    k= 0
    y=(2+x)/(1-2x)
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    (Original post by geekypoo)
    Well question one seemed abit too easy at times,
    Question two didnt see too bad, for hte implicite differentiation did people do this method

    y+ ln y = sinx
    dy/dx + 1/y dy/dx = cosx
    dy/dx (1 + 1/y) = cos x
    dy/dx ((y+1)/y) = cos x
    dy/dx = (ycosx)/(y+1)

    Also the integration question

    dy/dx = 5y/(2+x)(1-2x)

    ∫ 1/y dy = ∫ 5/(2+x)(1-2x) dx
    ln y = ∫(1/(2+x) + 2/(1-2x)) dx
    ln y = ln (2+x) - ln(1-2x) + c
    ln y = ln ((2+x)/(1-2x) +c
    y = (2+x)/(1-2x) + ec where ec = k
    y = (2+x)/(1-2x) + k
    when y = 2 x = 0
    2 = 2/1 + k
    k= 0
    y=(2+x)/(1-2x)
    yeah i did the top one like that. But for some strange reason my brain froze at that next one, the only question i didn't do i think. It looks pretty right to me the way you've done it though.
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    How did people do the double angle part of question three,
    x = 1 - cos2x and y=2sin2x

    so if y= x
    1-cos2x = 2sin2x
    1- (cos²x - sin²x) = 2(2sinxcosx)
    if 1 = cos²x + sin²x
    cos²x + sin²x - cos²x + sin²x = 2(2sinxcosx)
    2sin²x = 2(2sinxcosx)
    2sin²x/2sinxcosx = 2
    sinx/cosx = 2
    tanx = 2

    and the part where u do the equation thingy

    cos2x = 1-x and sin2x = y/2

    cos²2x = (1-x)² and sin²2x = y²/4

    sin²2x+cos²2x = (1-x)² + y²/4
    1 = 1 - 2x + x² + y²/4
    y²= 8x - 4x²= 4x(2-x)
    y= ±√(4x(2-x))

    Well thats if i remember the quesion correctly
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    I didn't think the comprehension was bad either, section a was ok, couldn't do the integration bit of question 2, no one in my class did! Yay maths is over!!
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    Isnt the integration in question 2 what i just did? It's ok for some who have finished, i still have D1, M3, M4 and P5 to do :rolleyes:
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    does anyone know what the grade boundaries were for the june 2004 exams (MEI)?
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    Well the grade boundaries are normally 80% for an A, 70% for a B, 60% for a C, 50% for a D, 40% for an E and lower for a U
    A: 48
    B: 42
    C: 36
    D: 30
    E: 24
    U < 24
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    I failed this paper so badly, I might as well have not turned up. Question 3 was awful, like, no marks awful/ , I screwed up the partial fractions integration question and many others. And then the comprehension paper was shockingly bad...
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    Well what were all the questions? can someone post them if they remember them all?
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    section a went really really well for me but i did horrible on the comprehension couldnt get anything to come out. I have to get 138/200 from this exam and mech 2 to get my A so i better keep my fingers crossed, wats done is done i suppose

    good luck everyone for results day
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    Well thats a B and a C really isnt it? i need to get an extra 31marks in my retakes to get A, but i did really badly in this back in january, and on p4
 
 
 
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