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    Hey guys, there is a question that I'd like to seek help on how to tackle.

    Given HCl(isotope 35) exhibits rotational absorption lines in the infrared at .....(a lot of wavenumber values),

    (a) identify the transitions and use a GRAPHICAL procedure to determine the rotational and centrifugal distortion constants.
    - I managed to get the transitions.

    - It is the graph I am unsure about. Atkins mention that taking centrigal distortion into account, the separation of lines should be given by

    2B(J+1) - 4D(J+1)^3

    I couldn't isolate to get a Y = mX + c graph, any ideas for me please? Thanks.
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    If you divide both sides by (J+1)3 you should get it into the y = mx + c form

    i.e. \frac{\nu}{(J+1)^3} = \frac{2B}{(J+1)^2} - 4D with axis y = \frac{\nu}{(J+1)^3} and x = \frac{1}{(J+1)^2}
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    (Original post by EierVonSatan)
    If you divide both sides by (J+1)3 you should get it into the y = mx + c form

    i.e. \frac{\nu}{(J+1)^3} = \frac{2B}{(J+1)^2} - 4D with axis y = \frac{\nu}{(J+1)^3} and x = \frac{1}{(J+1)^2}
    Thanks, EVS. I did divide by J+1 only to get a curve, didn't think I'd have to divide by (J+1)^3, hmm. Thanks again. Oh by the way, you happen to know any great book to read for molecular spectroscopy(physical)?
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    (Original post by shengoc)
    Thanks, EVS. I did divide by J+1 only to get a curve, didn't think I'd have to divide by (J+1)^3, hmm. Thanks again. Oh by the way, you happen to know any great book to read for molecular spectroscopy(physical)?
    Nah, the handouts for that part of my course were very good and so didn't warrant me needing to buy a specific text for that :nah:
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    Probably the best book is Modern Spectroscopy by J. Michael Hollas.
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    (Original post by shengoc)
    Thanks, EVS. I did divide by J+1 only to get a curve, didn't think I'd have to divide by (J+1)^3, hmm. Thanks again. Oh by the way, you happen to know any great book to read for molecular spectroscopy(physical)?
    Try and get hold of a copy of Bernath. It's fantastic...I preferred it to Hollas.
 
 
 
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