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# help needed with balancing equations please! watch

1. i'm basically confused about balancing equations..
foor example calcium carbonate reacts with nitric acid to form carbon dioxide, water and calcium nitrate right
so the unbalanced equation would be
CaCO3+H(NO)3 --> Ca(NO)3 + CO2 + H2O

then when it's balanced it will be
CaCO3+2H(NO)3 --> Ca(NO)3 + CO2 + H2O

i don't understand how that worksm doesnt the 2 in fron of HNO3 MEAN THAT THERE ARE 6 (NO)3s and tht it wont be balance with the 1 (NO)3 on the other side? im confused help!
2. It's HNO3 not H(NO)3 and Ca(NO3)2 not Ca(NO)3
3. (Original post by EierVonSatan)
It's HNO3 not H(NO)3 and Ca(NO3)2 not Ca(NO)3
so basically brakets should never be put in to avoid confusion right
4. (Original post by lagoom)
so basically brakets should never be put in to avoid confusion right
They should only be used to group atoms that are multiplied by the same amount:

3HNO3 = 3H, 3H, 9O
H(NO)3 = 1H, 3N, 3O
HN(O)3 = HNO3 = 1H, 1N, 3O
5. (Original post by EierVonSatan)
They should only be used to group atoms that are multiplied by the same amount:

3HNO3 = 3H, 3H, 9O
H(NO)3 = 1H, 3N, 3O
HN(O)3 = HNO3 = 1H, 1N, 3O
oh alright, im still pretty confused but thanks
how would you balance
NaHCO3 + H2SO4 -->H2O +CO2 + NA2SO4
(sodium hydrogen carbonate + sulphuric acid --> water + carbon dioxide + sodium sulphate)
6. (Original post by lagoom)
oh alright, im still pretty confused but thanks
how would you balance
NaHCO3 + H2SO4 -->H2O +CO2 + NA2SO4
(sodium hydrogen carbonate + sulphuric acid --> water + carbon dioxide + sodium sulphate)
The way to balance things is to take each atom individually:

Balance Na: 2NaHCO3 + H2SO4 --> H2O + CO2 + Na2SO4 [two Na on each side]

Balance H: 2NaHCO3 + H2SO4 --> 2H2O + CO2 + Na2SO4 [four H on each side]

Balance C: 2NaHCO3 + H2SO4 --> 2H2O + 2CO2 + Na2SO4 [2 C on each side]

Is now balanced
7. thank you!
nicely and clearly written aswell
8. (Original post by EierVonSatan)
The way to balance things is to take each atom individually:

Balance Na: 2NaHCO3 + H2SO4 --> H2O + CO2 + Na2SO4 [two Na on each side]

Balance H: 2NaHCO3 + H2SO4 --> 2H2O + CO2 + Na2SO4 [four H on each side]

Balance C: 2NaHCO3 + H2SO4 --> 2H2O + 2CO2 + Na2SO4 [2 C on each side]

Is now balanced
what about oxygen though, there's 10 on one side and 8 on the other
9. (Original post by lagoom)
what about oxygen though, there's 10 on one side and 8 on the other
10. (Original post by lagoom)
Ha, no problem

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Updated: October 11, 2009
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