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# Quick Quotient Question watch

1. Just a quick question here, not sure how id do this one...

Find the qutient and remainder when (x4 + x3 -5x2 -9) is divided by (x2 + x - 6)

Ducky
2. (Original post by ducky)
Just a quick question here, not sure how id do this one...

Find the qutient and remainder when (x4 + x3 -5x2 -9) is divided by (x2 + x - 6)

Ducky
Do you know how to do algebraic long division?
3. Yeah, but I can only divide in linear equations, i.e dividing by (x+1), not to sure for a polynomial...
4. This may help:
http://www.mathcentre.ac.uk/students.../resources/242
5. Thanks, that seems to have cleared thing up for me,

Ducky
6. >>>>>>>>x² + 1
x²+ x - 6√(x^4 + x³ -5x² + 0x -9)
>>>>>>>>x^4 + x³ - 6x²
>>>>>>>>>>>>>>>>>x² + 0x - 9
>>>>>>>>>>>>>>>>>x² + x - 6
>>>>>>>>>>>>>>>>>>>> -x -3

So the answer is x² + 1 + (-x-3)(x² + x - 6)

The remainder being -x - 3

Not sure if you want to put that fraction as partial fractions or not.

Hope this was all clear.

EDIT: Took me more than 3 minutes to type up! Sorry
7. Hehe. You could make the colour white to hide them. Or even better, try this:

>>>>>>>>x² + 1
x²+ x - 6√(x^4 + x³ -5x² + 0x -9)

(click reply to see the code I used)
8. (Original post by mockel)
Hehe. You could make the colour white to hide them. Or even better, try this:

>>>>>>>>x² + 1
x²+ x - 6√(x^4 + x³ -5x² + 0x -9)

(click reply to see the code I used)
Nice one man, thanks.
9. Was that C2?

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