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# Forces question watch

1. I worked out the following answer but not sure if the method I have used is correct. The question is that a boat is being pulled by tugs, one at 15 degrees with a force of 18000 N and the other with a force of 30000 N at an unknown angle and I have to work out the angle required to keep the boat travelling in a straight line.

I worked out the horizontal component of of the 18000 N and just guessed that the horinzontal force (which would actually look vertical on a diagram) would also need to be the same so I just substituted the value with the 30000 N into a trigonomic equation to get an angle. Could someone just please that this is the right method to use?
2. (Original post by Unknown?)

I worked out the horizontal component of of the 18000 N and just guessed that the horinzontal force (which would actually look vertical on a diagram) would also need to be the same so I just substituted the value with the 30000 N into a trigonomic equation to get an angle. Could someone just please that this is the right method to use?
Sounds about right, if you meant:

In order for the boat to continue in a straight line the sum of the forces acting perpendicular to that line must be zero.

So for the 18000 N force, this will be 18000 Sin 15.

For the 30000 N, this will be 30000 Sin a.

These two will be equal.
3. (Original post by ghostwalker)
Sounds about right, if you meant:

In order for the boat to continue in a straight line the sum of the forces acting perpendicular to that line must be zero.

So for the 18000 N force, this will be 18000 Sin 15.

For the 30000 N, this will be 30000 Sin a.

These two will be equal.
Thanks a lot that sounds right.

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