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# P2 Jan 05,help! watch

1. any one up for No.8 P2, jan. 2005. Need help! And need to get a grip with the whole Log thingy. Would appreciate it if any one could use this as a revision while Keying facts about 'Logs and it's extended Famlies' or outlining how to improve on them.
Thanks
2. well post the question please if u didnt get the answer from anyone that has the question
3. (Original post by yazan_l)
well post the question please if u didnt get the answer from anyone that has the question

8(d). Show that the equation;

1/2x) - 1 + ln(x/2)=0 can be rearranged into the form x = 2e ^(1 - (1/2x))

2 marks question.
4. (1/2x) - 1 + ln(x/2) = 0
ln(x/2) = 1- 1/2x

you know that : loga b = c can be written as : ac = b
so:ln(x/2) = 1- 1/2x
loge[ x/2 ] = 1- 1/2x
x/2 = e1- 1/2x
x = 2 e1- 1/2x
5. 'men' thanks a lot!
U up 4 one more?
6. ok go one! dont ask, just post the question
7. ln sinx = -ln secx, in d interval 0<x<90
8. and this;

log2 (2x+1) - log2x = 2
find x,
9. ln sinx = -ln secx
ln sinx = ln [secx]-1
sinx = sec-1x
sinx = cosx
tanx = 1
x = arctan1
x = 45o
10. log2 (2x+1) - log2x = 2
find x

log2(2x+1) - log2x = 2

logab - logac = loga(b/c)
log2 [(2x+1)/x] = 2
2² = [(2x+1)/x]
4x = 2x + 1
2x = 1
x = ½
11. any body from JORDAN here????
12. above u!
13. thanks mate yazan, are u taking P2 also?
and what tip do u think u can give in other 4 others & me to improve in that area(Logs)
14. no i've done P2
15. cool!
16. to be sure, lg - Log to d base 10, while ln is log to d base e, right?
17. ya right.

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