Integrating Trig Watch

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needmathshelp
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#1
Report Thread starter 13 years ago
#1
Any help would be much appreciated

The question is integrate:

xsec²x dx

Chris
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RichE
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#2
Report 13 years ago
#2
(Original post by needmathshelp)
Any help would be much appreciated

The question is integrate:

xsec²x dx

Chris
By parts

x tanx - Int tanx dx = xtanx + log(cosx) + C
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yusufu
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#3
Report 13 years ago
#3
(Original post by needmathshelp)
Any help would be much appreciated

The question is integrate:

xsec²x dx

Chris
integration by parts:
u = x
u' = 1
v' = sec²x
v = tanx

xtanx - ∫ tanx dx
xtanx + ln (cosx) + C
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sarah12345
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#4
Report 13 years ago
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i think u use intergration by parts

intergral du/dx v= uv- intergraldv/dx u

u=tan x
v=x

xtanx- intergral tanx= xtanx-ln|sec x| +c

i think!
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needmathshelp
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#5
Report Thread starter 13 years ago
#5
how come some people are saying the integral of tanx is ln|secx| and some are saying it is ln(cosx). This is what's confusing me. Thanks for the help!!!
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yusufu
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#6
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#6
-ln (secx) is the same as +ln (cosx)
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