The Student Room Group
Reply 1
This might help.
http://img300.echo.cx/img300/5185/swscan000046ur.jpg
Basically the stipulation is that the area R is to the right of x=4 and above y=0.25 (as otherwise the area would be infinite). Clearly y=0.25 at x=5 and there is no area above y=0.25 at x>5, so x=5 is the upper limit on the first integral.
The second integral subtracts the area below the line y=0.25 for 4<x<5, as the first integral finds the area bounded by the curve and x axis [note you could also have simply found the area of the rectangle instead of doing an integra[.
Reply 2
You are so clever!! :adore: Thankyou so much!! :biggrin:

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