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# general watch

1) Find the term independant of x in the expansion of (x-2/x)6

is there an idependant erm of x considering it is on both sides, would the answer be 64/x6

The point A is (5,6). prove that the nearest point on the circle (x-1)²+(y-3)² =4 is 3 units away from A.
I find the equation from the line between the centre of the circle and point A but then how do I prove it is 3 units away from it
2. see here for the first q.

http://www.thestudentroom.co.uk/show...21#post2389121
3. (Original post by Fermat)
see here for the first q.

http://www.thestudentroom.co.uk/show...21#post2389121
I can't do emperical formulas like that this is for my FSMQ(between gcse and as) I can't understand all that jargon
4. Sorry!

Can you use pascal's triangle to expand the expression?
5. (a+b)^6 = a^6 + 6.a^5b + 15a^4b^2 + 20a^3b^3 + 15a^2b^4 + 6ab^5 + b^6

does that help?

Find out in what term the powers cancel.
6. For example, if we substitute for a = x and b = -2/x in the middle term we get,

20a^3b^3 = 20x^3(-2/x)^3
7. (Original post by Meat Loaf Rocks)
...
I find the equation from the line between the centre of the circle and point A but then how do I prove it is 3 units away from it
Find out where the line intersects the (eqn of) the circle.

or,

Let O be the centre of the circle.
Find the distance OA
Subtract the radius (r=2) from this distance
Ans should then be 3.
8. (Original post by Meat Loaf Rocks)
So basically you do binomial expansion and then draw out an integer factor and that is the answer?
where the powers cancel - yep
9. Can you do the second uestion becasue the bit I got stuck on keeps reoccuring in every mock and I need to get a grip of it before the exam
10. O(1,3)
A(5,6)
OA =√{(5-1)² + (6-3)²}
OA = √{16 + 9}
OA = √25
OA = 5

let OA intersect circle at B

:. OB = 2
:. BA = 5 - 2 = 3
=============

11. God i feel like an idiot, that was simple
12. (Original post by Meat Loaf Rocks)
God i feel like an idiot, that was simple

you've been doing too much maths - common problem at the mo'
13. (Original post by Fermat)

you've been doing too much maths - common problem at the mo'
true I have done 3 2 hour mocks in da last 2 days,
lucky what i can do I can do easily and quickly, so it hasn't been too bad

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