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# Edexcel C3 Jun 05 - How Did It Go? watch

1. (Original post by TheWolf)
For one of the q you have to find when [modulus(x-1) -2] intersects 5x

it would only intersect with -(x-1) -2

so its -x + 1 -2 = 5x

6x = -1
x = -1/6

i cant remember the q totally correctly, so this might be wrong
gots the same
2. hey all

i found that exam pretty hard

i got a and b = -1 and -2 (dont know which is which)

i got R=2root13 or root52

i got the same alpha as above

i got x=-1/6 , i eliminated something like x=1/4

i got 14 years, although maybe it should have been rounded down to 13???, thats what one of my friends did

for one of the trig questions i got x=60, 300, 131.8, 228.2

for another trig question (i think the complicated one inclolving R and alpha etc) i got 0, pi, and something else but eliminated pi because it was out of range (0<=x<pi)

graphs looks like v through yaxis and W

thats all i remember for now

3. i think i got al tha same bar a few...cant memba which 1 ... but u did aite me thinkz
4. For the trig where involves R, i think you put √52sin(x+0.588) = 3 rather than =0, which most of you seem to have done? =o Hmm does anyone remember the exact q?
5. It's over
Now to revise for Biology tomorrow... =(
6. that -8/(x-1)^3 was as easy few marks (think it was 6 )
7. was the answer 13 or 14 years? do we round up or down or give a decimal???

i rounded up to 14, is that right?
8. Yea that should be right. Rounding down to 13 just doesn't make sense. =o
9. model solutions for this paper should be ready by tomorrow evening
10. (Original post by Hash)
2.12 radians for the long trig question (as well as 0 and pi)
pi was not included in the range, so that isn't right... (0<= x < pi)

11. (Original post by ArVi)
pi was not included in the range, so that isn't right... (0<= x < pi)

Did you put the R equation = 0. At the time I was pretty sure to put it = 3?
12. (Original post by TheWolf)
For one of the q you have to find when [modulus(x-1) -2] intersects 5x

it would only intersect with -(x-1) -2

so its -x + 1 -2 = 5x

6x = -1
x = -1/6

i cant remember the q totally correctly, so this might be wrong
Same answer and method! hope we're right!
13. (Original post by r2they)
was the answer 13 or 14 years? do we round up or down or give a decimal???

i rounded up to 14, is that right?
I rounded up to 14 too cuz it was like 13.93 or something.. When checking, i substituted back both 13 and 14 - 13 gave an answer too low and 14 was a little above, so I'm guessing 14 is right.
14. It should be 14 since there isn't going to be the right amount at the beginning of year 13. But there will be at year 14.
15. (Original post by TheWolf)
Did you put the R equation = 0. At the time I was pretty sure to put it = 3?
nope, i got the final equation =0

it was something like:

sin (x) [ √52 sin (x+0.588) - 3 ] = 0

So Sin(x) = 0 or √52 sin (x+0.588) - 3 = 0

So sin (x+0.588) = 3 ÷ √52
16. Yes I got sin (x+0.588) = 3 ÷ √52 as well. Might have calculated the final answers wrong.
17. i didnt manage to do that one.....
C3 was quite hard, harder than C2.....
i think the last q was the hardest of the paper...
18. (Original post by mackin boi)
did u get root 52 for R and .588 for alpha??
yup although I put it as 2sqr13
19. (Original post by ArVi)
nope, i got the final equation =0

it was something like:

sin (x) [ √52 sin (x+0.588) - 3 ] = 0

So Sin(x) = 0 or √52 sin (x+0.588) - 3 = 0

So sin (x+0.588) = 3 ÷ √52
That's right
20. (Original post by TheWolf)
For the trig where involves R, i think you put √52sin(x+0.588) = 3 rather than =0, which most of you seem to have done? =o Hmm does anyone remember the exact q?
I got the same thing although I don't recall the making it equal to 3 at all for that bit as that actual question gives you (what is at the time) a new formula and thus isn't equal to anything else...or I could be talkin aload of b*llox

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