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Maths C2 June 2005 watch

1. Post any answers you remember here!
All i remember is:

1. (3, -18)
2.
Binomial expansion question: -2 and 24
10a) Trapezium question, area R = 6.75 units²
10b) dy/dx = 2 - 16x-³
for y to be an increasing function, dy/dx > 0
therefore: 2 - 16x-³ > 0
2 > 16/x³
x³ > 8
x > 2

Agh! Cant remember what else i put
fill in anything you can remember so we can check answers!
2. http://www.thestudentroom.co.uk/t123856.html

3. 8)b ) 39,400
c)968,000...or something like that...

The circle question....don't remember what number...
a) (5,0)
b) r=4
c) (9,0)(1,0)
d) y= -2/7x -10/7 or 2x+7y+10=0

Trapezium...
b) 43.9
c) 5268...or somehting like that

Logs...
a) don't remember....
b) x=1/6

The sin and cosine questions- 0 <x <180....
a) 50, 110
b) 25.8, 154.2

a) 0.548
b) 0.58 and 2.56
4. for the logarithm part a, i got x=1/8 ??
5. (Original post by Revelation)
for the logarithm part a, i got x=1/8 ??
i got x=1/6
6. What is log(base2)(x-1)-log(base2)x=log(base2)7

7. (Original post by Kunster1337)
What is log(base2)(x-1)-log(base2)x=log(base2)7

When substract to same base logs, you can use division rule=
log2 x-1/x= log2 7
knocking of the log2 gives

x-1/x=7
x-1=7x
-1=6x
x= -1/6
8. gay thats where i went wrong
got to: x-1=7x then went to 1=8x
9. for logs part a, was it 5^x = 7 ?
x= log7/log5 = 1.2
10. geometric series, a=35000, r=1.04
a) n = 2008-2005 = 3 => U_3 = 35000*1.04^2 = 37900 (to the nearest £100)
b) n= 2024-2005 = 19 = > S_19 = 35000*(1.04^19 - 1)/(0.04) = £968 000 (to the nearest £1000)
11. (Original post by Revelation)
geometric series, a=35000, r=1.04
a) n = 2008-2005 = 3 => U_3 = 35000*1.04^2 = 37900 (to the nearest £100)
b) n= 2024-2005 = 19 = > S_19 = 35000*(1.04^19 - 1)/(0.04) = £968 000 (to the nearest £1000)
Wasn't the last part to the power of 20, because he still gets a salary on the year he retires?
12. wasnt n=20 for the GP question?
13. (Original post by Revelation)
geometric series, a=35000, r=1.04
a) n = 2008-2005 = 3 => U_3 = 35000*1.04^2 = 37900 (to the nearest £100)
b) n= 2024-2005 = 19 = > S_19 = 35000*(1.04^19 - 1)/(0.04) = £968 000 (to the nearest £1000)
wouldn't 'n' be 20 years between 2005 and 2024 ??
14. sigh yet another question wrong.
15. and there was me thinking it was an easy paper. For the intergration i got R=6.75units2. Umm,
tiangle question? Sin 0.5/7 = Sin B/8
B = 0.580 (3dp)
16. What did the question actually say he retires in 2024?

(Original post by Revelation)
and there was me thinking it was an easy paper. For the intergration i got R=6.75units2. Umm,
tiangle question? Sin 0.5/7 = Sin B/8
B = 0.580 (3dp)
I hope you didnt do sin inverse. The questions wanted Sin B not B.
17. (Original post by Revelation)
and there was me thinking it was an easy paper. For the intergration i got R=6.75units2. Umm,
tiangle question? Sin 0.5/7 = Sin B/8
B = 0.580 (3dp)
i got that too
i still feel the jan c2 paper was easier
18. yeah - n=20... so the final answer would be £1042000 (nearest 1000)...
19. model solutions for this exam will be ready by tomorrow evening hopefully
20. (Original post by mala2k)
What did the question actually say he retires in 2024?

I hope you didnt do sin inverse. The questions wanted Sin B not B.
I got Sin B = 0.571
this is the same as Sin x as it was in radians?

Is that correct?

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