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    Post any answers you remember here!
    All i remember is:

    1. (3, -18)
    2.
    Binomial expansion question: -2 and 24
    10a) Trapezium question, area R = 6.75 units²
    10b) dy/dx = 2 - 16x-³
    for y to be an increasing function, dy/dx > 0
    therefore: 2 - 16x-³ > 0
    2 > 16/x³
    x³ > 8
    x > 2

    Agh! Cant remember what else i put
    fill in anything you can remember so we can check answers!
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    http://www.thestudentroom.co.uk/t123856.html

    thats the proper thread m8
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    8)b ) 39,400
    c)968,000...or something like that...

    The circle question....don't remember what number...
    a) (5,0)
    b) r=4
    c) (9,0)(1,0)
    d) y= -2/7x -10/7 or 2x+7y+10=0

    Trapezium...
    b) 43.9
    c) 5268...or somehting like that

    Logs...
    a) don't remember....
    b) x=1/6

    The sin and cosine questions- 0 <x <180....
    a) 50, 110
    b) 25.8, 154.2

    The radians question....
    a) 0.548
    b) 0.58 and 2.56
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    for the logarithm part a, i got x=1/8 ??
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    (Original post by Revelation)
    for the logarithm part a, i got x=1/8 ??
    i got x=1/6 :confused:
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    What is log(base2)(x-1)-log(base2)x=log(base2)7

    Please go thru it!
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    (Original post by Kunster1337)
    What is log(base2)(x-1)-log(base2)x=log(base2)7

    Please go thru it!
    When substract to same base logs, you can use division rule=
    log2 x-1/x= log2 7
    knocking of the log2 gives

    x-1/x=7
    x-1=7x
    -1=6x
    x= -1/6
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    gay thats where i went wrong
    got to: x-1=7x then went to 1=8x
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    for logs part a, was it 5^x = 7 ?
    x= log7/log5 = 1.2
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    geometric series, a=35000, r=1.04
    a) n = 2008-2005 = 3 => U_3 = 35000*1.04^2 = 37900 (to the nearest £100)
    b) n= 2024-2005 = 19 = > S_19 = 35000*(1.04^19 - 1)/(0.04) = £968 000 (to the nearest £1000)
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    (Original post by Revelation)
    geometric series, a=35000, r=1.04
    a) n = 2008-2005 = 3 => U_3 = 35000*1.04^2 = 37900 (to the nearest £100)
    b) n= 2024-2005 = 19 = > S_19 = 35000*(1.04^19 - 1)/(0.04) = £968 000 (to the nearest £1000)
    Wasn't the last part to the power of 20, because he still gets a salary on the year he retires?
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    wasnt n=20 for the GP question?
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    (Original post by Revelation)
    geometric series, a=35000, r=1.04
    a) n = 2008-2005 = 3 => U_3 = 35000*1.04^2 = 37900 (to the nearest £100)
    b) n= 2024-2005 = 19 = > S_19 = 35000*(1.04^19 - 1)/(0.04) = £968 000 (to the nearest £1000)
    wouldn't 'n' be 20 years between 2005 and 2024 ??
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    sigh yet another question wrong.
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    and there was me thinking it was an easy paper. For the intergration i got R=6.75units2. Umm,
    tiangle question? Sin 0.5/7 = Sin B/8
    B = 0.580 (3dp)
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    What did the question actually say he retires in 2024?

    (Original post by Revelation)
    and there was me thinking it was an easy paper. For the intergration i got R=6.75units2. Umm,
    tiangle question? Sin 0.5/7 = Sin B/8
    B = 0.580 (3dp)
    I hope you didnt do sin inverse. The questions wanted Sin B not B.
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    (Original post by Revelation)
    and there was me thinking it was an easy paper. For the intergration i got R=6.75units2. Umm,
    tiangle question? Sin 0.5/7 = Sin B/8
    B = 0.580 (3dp)
    i got that too
    i still feel the jan c2 paper was easier
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    yeah - n=20... so the final answer would be £1042000 (nearest 1000)...
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    model solutions for this exam will be ready by tomorrow evening hopefully
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    (Original post by mala2k)
    What did the question actually say he retires in 2024?



    I hope you didnt do sin inverse. The questions wanted Sin B not B.
    I got Sin B = 0.571
    this is the same as Sin x as it was in radians?

    Is that correct?
 
 
 
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