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    (Original post by mala2k)
    What did the question actually say he retires in 2024?



    I hope you didnt do sin inverse. The questions wanted Sin B not B.
    I did but after checking through my paper i spotted it wanted "sin x"
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    (Original post by Kunster1337)
    I got Sin B = 0.571
    this is the same as Sin x as it was in radians?

    Is that correct?
    i got Sin B = (8/7)*Sin(0.5) = 0.548
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    the cross section of the river i _think_ i got 43.86m2 and then the flow of water in a minute (2*60)*43.86 = 5260m2 (3sf)
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    That sounds like what I got as well... I'm glad that a lot of my answers are matching with what's on here - but unfortunately I got R = 2.75 for the last question which is probably wrong, it was an 8 mark question as well - I just hope I manage to get an A in maths overall (C1 went well and S1 did not =/).
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    I got 6.75 for the last question too. Did you all just sub in x=2 to part b of it? And then get the second derivative so that it's maximum, and as the value of x gets higher, the second derivative gets lower, so it's more negative, therefore more maximum? Because I just totally rambled.

    Really hope I can get an A. Not sure. The things I know I messed up: I put n=19 for the geometric series question. I also know I did the river question (trapezium rule) wrong - the last part. I got 7.31 which is really small! Does anyone know how you were meant to do that one? The volume of water per min?
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    i forgot how to prove the sum of geometric progression, lol. other than that, all seemed to go well. i was suprised by the one about the river, think it mayve scared some non physicists, even though its ks3 science knowlege needed. hopefully will get >90%
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    i used my answer to the above part, 43.something, i think. and then since it was 2ms^-1 going for a minute, it will be 120 meters long in 1 minute. so my area multiplied by length = volume
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    (Original post by matt.forster)
    i used my answer to the above part, 43.something, i think. and then since it was 2ms^-1 going for a minute, it will be 120 meters long in 1 minute. so my area multiplied by length = volume
    So what was the real anwser to that question.....

    I got like 7.31 but i know thats wrong.
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    erm i got 5200, to the nearest 100, i think.
    i dont know what i did in the first palce though, when i added up y1--yn-1, i got something like 42. lol. ended up with a huge number - thank god for checking through.
    i also mis-read the intergration question, i saw 8/x^2, as 8/x, and so when intergrated, it became 0!, and then when x=4 - when x=1, igot 0 for the area!
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    (Original post by fisfos815)
    8)b ) 39,400
    c)968,000...or something like that...

    The circle question....don't remember what number...
    a) (5,0)
    b) r=4
    c) (9,0)(1,0)
    d) y= -2/7x -10/7 or 2x+7y+10=0
    Can anyone confirm part d for me please? Because I got 2x+7y-10 , but I may be wrong.

    Also, I was just wondering how you all did the binomial expansion question (part b) - I messed it up; I got -2, but then for the other value I got 144! Can anyone remember how many marks it was?

    Thanks to anyone who replies.
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    was the binomial expansion something like (1+px)12
    where 2p is x coefficient and -11q is x2 coefficient??
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    (Original post by Revelation)
    was the binomial expansion something like (1+px)12
    where 2p is x coefficient and -11q is x2 coefficient??
    Yup das da question. part a was expand up to the x^2 value.. part b was to find the value of p and q
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    What did people get for the area under the curve Q10? I got 6.75 units2
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    (Original post by C4>O7)
    What did people get for the area under the curve Q10? I got 6.75 units2
    Well done that means you have got minimum 8 out of 75 in that paper already.

    Maybe you should differentiate that so you can find the maximum :p:
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    thnks lol
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    (Original post by Mits)
    Can anyone confirm part d for me please? Because I got 2x+7y-10 , but I may be wrong.
    I got that
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    (Original post by Kavanne)
    I got that
    Thats great, thanks!
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    (Original post by C4>O7)
    What did people get for the area under the curve Q10? I got 6.75 units2
    i got that.
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    (Original post by Revelation)
    geometric series, a=35000, r=1.04
    a) n = 2008-2005 = 3 => U_3 = 35000*1.04^2 = 37900 (to the nearest £100)
    b) n= 2024-2005 = 19 = > S_19 = 35000*(1.04^19 - 1)/(0.04) = £968 000 (to the nearest £1000)

    If:

    2005=a
    2006=ar
    2007=ar^2
    2008=ar^3 ??

    well that is wat i did... 35000*1.04^3 = 39400 (to the nearest £100)... problem is that i may have read the question wrong!
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    (Original post by np_desi)
    If:

    2005=a
    2006=ar
    2007=ar^2
    2008=ar^3 ??

    well that is wat i did... 35000*1.04^3 = 39400 (to the nearest £100)... problem is that i may have read the question wrong!
    Yup i did the same as you even did the embarrassing bit and counted out the years on my hand to make i sure i got them right 2005, 2006 ,2007, and 2008 n=4 for that part. Tis wot i did neway
 
 
 
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