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# Edexcel P2 After-test Discusion watch

1. (Original post by Steve8052)
Shudnt this be 2pi(2 2/3-ln3) = 4 2/3pi - 2pi ln 3.

You got (2pi/3)(4+ln3) = 4 2/3pi - 2/3pi ln 3
v=pi[x+2lnx-(1/x)] with limits 1,3.
v=pi[(8/3)+2ln3]
v=(pi/3)(8+6ln3)
v=(2pi/3)(4+3ln3)
There's no subtraction between logarithmic and fraction.
2. I think the equation of the line was y=(x-1)/x tho
3. I thought the paper was really nice (and im by no means a mathmatician - I reckon i got around 73/75)

1. a) x = lg8/lg5 = 1.29
b) x = 1/6

2a) 1 + 12px + 66p²x²
b) P = -2 q = 24

3a) x = 4 y = 1.600, x = 12 y = 3.394, x = 16 y = 3.200
b) 43.86m²
c) 6263.2m³

4a) Im not gonna write out my working but it all worked out ok,
b) f^-1(X) = 2/x + 1
c) X = +/-2 (the reason i said it could be -2 is that in function g x can be any real number, function g contains x² therefore this will make any negative positive allowing for the condition on f that x > 1 - did anyone else do this???)

5a) π(8/3 + 2ln3)
b) i couldnt remember the formula for volume of cone - will hopefully get one mark for subtracting something - i tried to integrate the formula for curved surface area this gave me 1/2πr²h - so close but so far

6a) 3e^x - 1/2x
b) it worked with a bit of rearranging
c) x1 = 0.0613
x2 = 0.1568
x3 = 0.1425
x4 = 0.1445

d) f'(0.14425) = -0.000685
f'(0.14435) = 0.002
change in sign therefore root intbetween

7.a) see attached picture
b) see attched picture
c) a = -2 b = -1
d) x = -1/6

8. a) tan θ = -1/3√3
b) i) use of double angle formula and cos²x + sin²x = 1
ii) x = 3π/2 π/6 5π/6
iii) it all cancelled down to
cos²x + sin²x = 1
then with a little substitution it showed that 1=1

I have a copy of the paper if anyone would like specific questions posted.
Let me know what u think
Cheers
Attached Images

4. (Original post by Gaz031)
v=pi[x+2lnx-(1/x)] with limits 1,3.
v=pi[(8/3)+2ln3]
v=(pi/3)(8+6ln3)
v=(2pi/3)(4+3ln3)
There's no subtraction between logarithmic and fraction.
i left my answer as the bold bit above
5. (Original post by Steve8052)
I think the equation of the line was y=(x-1)/x tho
The equation of the curve was y=(x+1)/x. I remember that distinctly as when flicking back through the paper f^-1(x)=(x+2)/x in the previous question was very similar to the equation of the curve in this question.
6. c) X = +/-2 (the reason i said it could be -2 is that in function g x can be any real number, function g contains x² therefore this will make any negative positive allowing for the condition on f that x > 1 - did anyone else do this???)
I left it as +-2 as fg(x) implies g is carried out first and g is an even function.
7. (Original post by josklkr)
I thought the paper was really nice (and im by no means a mathmatician - I reckon i got around 73/75)

1. a) x = lg8/lg5 = 1.29
b) x = 1/6

2a) 1 + 12px + 66p²x²
b) P = -2 q = 24

3a) x = 4 y = 1.600, x = 12 y = 3.394, x = 16 y = 3.200
b) 43.86m²
c) 6263.2m³

4a) Im not gonna write out my working but it all worked out ok,
b) f^-1(X) = 2/x + 1
c) X = +/-2 (the reason i said it could be -2 is that in function g x can be any real number, function g contains x² therefore this will make any negative positive allowing for the condition on f that x > 1 - did anyone else do this???)

5a) π(8/3 + 2ln3)
b) i couldnt remember the formula for volume of cone - will hopefully get one mark for subtracting something - i tried to integrate the formula for curved surface area this gave me 1/2πr²h - so close but so far

6a) 3e^x - 1/2x
b) it worked with a bit of rearranging
c) x1 = 0.0613
x2 = 0.1568
x3 = 0.1425
x4 = 0.1445

d) f'(0.14425) = -0.000685
f'(0.14435) = 0.002
change in sign therefore root intbetween

7.a) see attached picture
b) see attched picture
c) a = -2 b = -1
d) x = -1/6

8. a) tan θ = -1/3√3
b) i) use of double angle formula and cos²x + sin²x = 1
ii) x = 3π/2 π/6 5π/6
iii) it all cancelled down to
cos²x + sin²x = 1
then with a little substitution it showed that 1=1

I have a copy of the paper if anyone would like specific questions posted.
Let me know what u think
Cheers
What was the equation to the graph for finding the volume of revolution?
8. (Original post by Steve8052)
What was the equation to the graph for finding the volume of revolution?
It was y = (x + 1)/x
9. LOL thanks!! oops my bad memory!! Thought I worked through the question with y=(x-1)/x but remembered now.
10. Btw could you mind posting the marks up for the questions thanks. Trying to work out how many marks I lost.
11. ^^ yeh
12. (Original post by Steve8052)
LOL thanks!! oops my bad memory!! Thought I worked through the question with y=(x-1)/x but remembered now.
no problem, what do u think about the +/- 2 thing in question 4??
13. (Original post by Steve8052)
Btw could you mind posting the marks up for the questions thanks. Trying to work out how many marks I lost.
Lol same here
14. http://www.thestudentroom.co.uk/t121212.html

the raw marks needed for an A has never been more than 61, was this paper really so easy????
15. (Original post by josklkr)
no problem, what do u think about the +/- 2 thing in question 4??
Sounds decent, I only wrote down the positive answer tho because like you said it said something like x>1?? cant remember, maybe no. of marks will depict what is required.
16. (Original post by tobyclark)
http://www.thestudentroom.co.uk/t121212.html

the raw marks needed for an A has never been more than 61, was this paper really so easy????

June 2003, Raw Mark 65/75 = 80UMS

Regards
17. well if it is +-2 then i think i will be getting a very high ums...
18. Alright here are the marks for each questoin
1a) 3
b) 3

2a) 2
b) 4

3a) 2
b) 4
c) 2

4 a) 4
b) 3
c) 3

5a) 7
b) 3

6a) 3
b) 2
c) 2
d) 2

7. a) 2
b) 3
c)2
d)4

8a) 5
b i) 2
ii) 5
iii) 3
19. (Original post by devesh254)
well if it is +-2 then i think i will be getting a very high ums...
Will be 66-67/75 IMO, although i messed up as usual haha...
20. pi (8/3 + 2ln3) ?

Couldnt you have left it like that?

Oh and, i dont think the grade boundries will be low or high. i think 60-62 for an A sounds about right - the general feeling about this paper is people either found it quite easy or quite hard.

And also, a paper easy to make a mistake in especially the trig question.

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