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    surely it doesnt matter what the grade boundaries are for the overall grade. what matters is how all ur exam grades add up.
    UMS for A is 480/600, so if you count up UMS marks from last year and take it away from 480, itll give u how many marks you need to get in your A2 exams to get an A overall.

    (i went a bit mad with this and did it for physics and biology too...makes me feel better knowing i only need 60% average in salters biology for my B (woohoo)
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    Grade boundaries do matter though. If you get 65/75, which is nearly 87%, and the grade boundary for an A is 66, then the most you can get is 79/100 UMS... if you need an A, that'd be costly. Meh, I don't care anyway. I had two exams today that didn't leave me panicking. This is good. Any answer to my question anybody?
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    No i dont think it would be a problem. Still the same EXACT answer anyway.
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    Uhu, that's what I thought, and I never know which to leave it as. I had time left so I thought I'd change it, and, typical to me, I panicked anyway.
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    (Original post by josklkr)
    5a) π(8/3 + 2ln3)
    b) i couldnt remember the formula for volume of cone - will hopefully get one mark for subtracting something - i tried to integrate the formula for curved surface area this gave me 1/2πr²h - so close but so far
    This is odd. What I did for this question is found the equation of the tangent, then found the volume of revolution for the triangle and then subtracted that from the volume under the curve.

    Didn't anyone else try that? (apparently not from what i've seen here). I got (2ln 3 - 16)pi.

    I'm pretty sure that's right, because how can the volume of revolution thing give you the wrong answer? .... does anyone know why this might have happened? can anyone try doing it with volumes of rev?
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    (Original post by pkchips)
    This is odd. What I did for this question is found the equation of the tangent, then found the volume of revolution for the triangle and then subtracted that from the volume under the curve.

    Didn't anyone else try that? (apparently not from what i've seen here). I got (2ln 3 - 16)pi.

    I'm pretty sure that's right, because how can the volume of revolution thing give you the wrong answer? .... does anyone know why this might have happened? can anyone try doing it with volumes of rev?
    2l3 - 16 is negative, so it cant be right
    I followed the same technique as you, and got pie(2/3 + 2ln3)
    The triangles volume was 2pie i think
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    I did equation of the tangent, using the point (3,0) as my point so I got a slightly more simple equation, volume of a revolution, and took that away from my orignal, and ended up with Piln9. I have no idea if it was right, but it seemed to be a sensible answer considering the set up of the question, and, some other people had it.
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    (Original post by Charlottie)
    I thought it was a relatively easy paper, because I hammered into revision after doing badly in January. Hopefully, I'm not delusional and I have done well. One question... in the volume of a revolution questions, I changed 2ln3 to ln9... or whatever the hell ln whatever the hell, I just raised it to the power, that is ok right?

    EDIT: I'm a ******, I've typed it the wrong way round.

    Yeh that's fine... What part of Notts you from?..
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    (Original post by sequence123)
    2l3 - 16 is negative, so it cant be right
    I followed the same technique as you, and got pie(2/3 + 2ln3)
    The triangles volume was 2pie i think
    I think you mean the 'cone's volume? It was (1/3)(pi)(2^2)(2)=8pi/3 IIRC.
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    (Original post by sequence123)
    2l3 - 16 is negative, so it cant be right
    I followed the same technique as you, and got pie(2/3 + 2ln3)
    The triangles volume was 2pie i think
    that is so close to what i got i got tri volume to be 2 2/3pi though

    so when I took one from the other the volume of R to be just 2ln3
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    This is what I eventually got (yeah, I know it wasn't one, but I can't remember the number and I know it was the same):

    pi(1 +ln 9) - pi(1)
    pi1 + piln9 -pi1
    pi (1+ln9 - 1)
    piln9

    And I'm from North Notts, I'm right on the Yorkshire border.
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    (Original post by pkchips)
    This is odd. What I did for this question is found the equation of the tangent, then found the volume of revolution for the triangle and then subtracted that from the volume under the curve.

    Didn't anyone else try that? (apparently not from what i've seen here). I got (2ln 3 - 16)pi.

    I'm pretty sure that's right, because how can the volume of revolution thing give you the wrong answer? .... does anyone know why this might have happened? can anyone try doing it with volumes of rev?
    wow that's so annoying. I retried the question and see where I went wrong. I went from:

    y - 2 = -x + 1

    to y = -x - 1

    when it should have been y = -x + 3

    a simple error in carrying forward a line of working. I absolutely hate it when that happens.

    oh well I think I got everything else in the paper right...
 
 
 
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